A wheel of diameter 30.0 cm starts from rest and rotates with a constant angular acceleration of 3.50 rad/s2 . At the instant th
e wheel has completed its second revolution, compute the radial acceleration of a point on the rim in two ways.
1 answer:
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The heat released by the gas is -225 J
Explanation:
First of all, we have to calculate the change in internal energy of the gas, which for a diatomic gas is given by
where
n = 0.235 mol is the number of moles
is the gas constant
is the change in temperature
Substituting,
Now we can us the 1st law of thermodynamics to find the heat absorbed/released by the gas:
where
is the change in internal energy
Q is the heat
W = 205 J is the heat done by the gas
Solving for Q,
Since the sign is negative, it means the heat has been released by the gas.
Learn more about thermodynamics:
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