Answer:
4462.0927 W
Explanation:
= Emissivity of the panel = 1
= Stefan-Boltzmann constant =
T = Temperature = (273.15+6)
Area of the panel is given by
The power radiated is given by
The power radiated from each panel is 4462.0927 W
A wheel of diameter 30.0 cm starts from rest and rotates with a constant angular acceleration of 3.50 rad/s2 . At the instant th
e wheel has completed its second revolution, compute the radial acceleration of a point on the rim in two ways.
1 answer:
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Answer:
Change in mechanical energy = work done by friction
so it is equal to
Explanation:
As we know that change in mechanical energy must be equal to the work done by non conservative forces only
So here when block moves down the inclined plane then the work done by friction force is given as
here we have
here we know that
so we have
Now the friction force on the block is given as
now work done by the friction is given as