Answer: A. 4 unpaired electrons
B. Zero unpaired electrons
C. 1 unpaired electron
D. 5 unpaired electrons
E. Zero unpaired electrons
Explanation:
In A, Oxidation state of Co is +3 and Electronic configuration is [Ar]3d6
F is weak field ligand, causes no pairing of Electrons hence it has 4 unpaired electrons&2 are paired in t2g orbitals (dXY)
In B , Mn is in +3 with electronic configuration 3d4&CN is a strong field ligand hence causes pairing of Electrons hence it results 0 unpaired electron
In C, Mn is in +2 with electronic configuration 3d5 sinceCN is a strong field ligand hence it leaves one unpaired electron
In D, Mn is in+2 with 3d5& five unpaired electrons since cl is a weak field ligand causes no pairing.
In E, Rh is in +3, with d6 configuration and it is a low spin complex hence pairing of Electrons involved. So it leaves zero unpaired electrons.
A calcium ...... i believe this is the answer
1 cup = 2 pints
48 × 2 = 96 pints
HOPE THIS HELPED
:)
Answer: potassium and rubidium
Explanation:
1) The group 1 of the periodic table contain six elements namely Lithium(Li), Sodium(Na),Potassium(K),Rubidium(Rb),Cesium(Cs) and Francium(Fr). These metals are called alkali metals because they form alkalies( i.e. strong bases capable of neutralizing acids) when they react with water.
2) The heavier alkali metals (K, Rb, and Cs) react so vigorously that they invariably explode.
3) This trend, which is not consistent with the relative magnitudes of the reduction potentials of the elements, serves as another example of the complex interplay of different forces and phenomena—in this case, kinetics and thermodynamics.
B is the answer. It is the steepest