There are many ways to test and identify metal. The easiest way is observing its color. Also how reflective it is. Other ways would be boiling point, melting point, density, or conductivity of the metal.
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Answer:
The correct appropriate will be Option 1 (Acid anhydrides are less stable than esters so the equilibrium favors the ester product.)
Explanation:
- Acid anhydride, instead of just a carboxyl group, is typically favored for esterification. The predominant theory would be that Anhydride acid is somewhat more volatile than acid. This is favored equilibrium changes more toward the right of the whole ester structure.
- Extremely responsive than carboxylic acid become acid anhydride as well as acyl chloride. Thus, for esterification, individuals were most favored.
The other options offered are not relevant to something like the scenario presented. So, the solution here is just the right one.
Answer:
2PbSO4 → 2PbSO3 + O2
Explanation:
in original equation we notice that we have one extra oxygen, which we cannot form a O2 with, so by multiplying everything else by 2, we get 2 extra oxygen
<span>We know that protons gives positive charge, neutrons no charge and electrons negative, then +14 - 12 = +2
So the charge of the atom is sign positive and magnitude 2</span>
