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guapka [62]
1 year ago
5

Compare and contrast aldehydes, ketones and alcohols in terms of structure, physical properties and chemical properties.

Chemistry
1 answer:
Ksivusya [100]1 year ago
7 0

The functional group of aldehyde is -CHO

The functional group of ketone is -CO-

The functional group of alcohol is -OH

<h2>STRUCTURES</h2><h3>ALDEHYDE</h3>

The carbonyl group is bounded to at least one hydrogen atom

<h3>KETONE</h3>

The carbonyl group is bounded to two carbon atom

<h3>ALCOHOL</h3>

Organic molecules assembled from carbon, oxygen and hydrogen.

<h2>PHYSICAL PROPERTIES</h2><h3>COLOUR</h3>

Aldehyde. alcohols and ketone are colourless

<h3>ODOURS</h3>

Alcohols are sweet smell expect glycerol

Aldehyde have unpleasant odors

ketone have pleasant odors

<h3>BOILING POINT</h3>

Alcohol , Aldehyde and Ketone have High boiling point

<h3>STATE</h3>

Alcohol, Aldehyde and Ketone are in liquid state

<h2>CHEMICAL PORPERTIES</h2><h3>OXIDATION </h3>

Alcohol oxidized to form carboxylic acid

Aldehyde oxidized to form carboxylic acid

Ketone oxidized to form  carboxylic acid

Learn more about alcohol, aldehyde and ketone on

https://brainly.ph/question/11006608

#SPJ4

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Anni [7]

Answer:

Ka = 4.76108

Explanation:

  • CO(g) + 2H2(g) ↔ CH3OH(g)

∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]

                      [ ]initial         change         [ ]eq

CO(g)              0.27 M       0.27 - x        0.27 - x

H2(g)              0.49 M       0.49 - x        0.49 - x

CH3OH(g)          0                0 + x               x = 0.11 M

replacing in Ka:

⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)

⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)

⇒ Ka = (0.11) / (0.38)²(0.16)

⇒ Ka = 4.76108

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Hope this helps! :)

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