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1 year ago

Compare and contrast aldehydes, ketones and alcohols in terms of structure, physical properties and chemical properties.

Chemistry

1 answer:

Ksivusya [100]1 year ago

7 0

The functional group of aldehyde is -CHO

The functional group of ketone is -CO-

The functional group of alcohol is -OH

<h2>STRUCTURES</h2><h3>ALDEHYDE</h3>

The carbonyl group is bounded to at least one hydrogen atom

<h3>KETONE</h3>

The carbonyl group is bounded to two carbon atom

<h3>ALCOHOL</h3>

Organic molecules assembled from carbon, oxygen and hydrogen.

<h2>PHYSICAL PROPERTIES</h2><h3>COLOUR</h3>

Aldehyde. alcohols and ketone are colourless

<h3>ODOURS</h3>

Alcohols are sweet smell expect glycerol

Aldehyde have unpleasant odors

ketone have pleasant odors

<h3>BOILING POINT</h3>

Alcohol , Aldehyde and Ketone have High boiling point

<h3>STATE</h3>

Alcohol, Aldehyde and Ketone are in liquid state

<h2>CHEMICAL PORPERTIES</h2><h3>OXIDATION </h3>

Alcohol oxidized to form carboxylic acid

Aldehyde oxidized to form carboxylic acid

Ketone oxidized to form carboxylic acid

Learn more about alcohol, aldehyde and ketone on

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Why are the molecules of hydrocarbons nonpolar?

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3 years ago

Read 2 more answers

1. the mass of one electron is

kupik [55]

Answer:

Mass of one electron is 9.1 × 10⁻³¹ kg

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Mass of one neutron is 1.675 × 10⁻²⁷ Kg

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2 years ago

A 21.0 kg child is running at a velocity of 2.50 m/s. The child is carrying a 2.25 kg gallon of milk. What is the momentum of th

KIM [24]

Answer: The momentum of the child and milk together is 58.125 kg.m/s

Explanation:

Momentum is defined as the product of object's mass and velocity.

Mathematically,

$p=mv$

where, p = momentum

m = mass of the object

v = velocity of the object

In the given question, we are given that a child of mass 21.0 kg is carrying a gallon of milk having mass 2.25 kg and running with a velocity of 2.5 m/s. Hence, the momentum by both milk and child will be:

$p=(m_{child}+m_{milk})v$ ....(1)

Given:

$m_{child}=21.0kg\\m_{milk}=2.25kg\\v=2.5m/s\\p=?kg.m/s$

Putting values in equation 1, we get:

$p=(21+2.25)kg\times 2.5m/s=58.125kg.m/s$

Hence, the momentum of the child and milk together is 58.125 kg.m/s

7 0

3 years ago

An automobile tire at 30°C has a pressure of 3.00 atm. Temperature decreases to -5°C. Assume that there is no volume change in t

dmitriy555 [2]

Answer:

P₂ = 2.7 atm

Explanation:

Given data:

Initial temperature = 30°C

Initial pressure = 3.00 atm

Final temperature = -5°C

Final pressure = ?

Solution:

Initial temperature = 30°C = 30 + 273 = 303 K

Final temperature = -5°C = -5 + 273 = 268 K

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

3.0 atm / 303 K = P₂/268 K

P₂ = 3.0 atm × 268 K / 303 K

P₂ = 804 atm. K /293 K

P₂ = 2.7 atm

7 0

3 years ago

The pressure on 2.50 L of gas is changed from 4.5 atm to 2.2 atm. What is the new volume of gas?

swat32

Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question we have

$V_2 = \frac{2.5 \times 4.5}{2.2} = \frac{11.25}{2.2} \\ = 5.1136666...$

We have the final answer as

Hope this helps you

8 0

3 years ago