Answer:
a. Amplitude = 0.244 meters
b. Period = 1.62 seconds
c. Frequency = 0.6173 Hz
Explanation:
a.
With the position goes from 0.122 meters to -0.122 meters (negative because it is in the opposite side of the equilibrium point), the amplitude is the maximum value minus the minimum value:
Amplitude = 0.122 - (-0.122) = 0.122 + 0.122 = 0.244 meters
b.
The period is the amount of time the object takes to arrive in the same position again. So, if it takes 0.81 seconds to go to -0.122 m, it will take another 0.81 seconds to come back to 0.122 m, so the period is the sum of these two times:
Period = 0.81 + 0.81 + 1.62 seconds
c.
The frequency of the movement is the inverse of the period:
Frequency = 1 / Period
So if the period is 1.62 seconds, the frequency is:
Frequency = 1 / 1.62 = 0.6173 Hertz
Answer:
7066kg/m³
Explanation:
The forces in these cases (air and water) are: Fa =mg =ρbVg Fw =(ρb −ρw)Vg where ρw = 1000 kg/m3 is density of water and ρb is density of the block and V is its density. We can find it from this two equations:
Fa /Fw = ρb / (ρb −ρw) ρb = ρw (Fa /Fa −Fw) =1000·(1* 21.2 /21.2 − 18.2)
= 7066kg/m³
Explanation:
Answer:
p2 = 9.8×10^4 Pa
Explanation:
Total pressure is constant and PT = P = 1/2×ρ×v^2
So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2
from continuity we have ρ×A1×v1 = ρ×A2×v2
v2 = v1×A1/A2
and
r2 = 2×r1
then:
A2 = 4×A1
so,
v2 = (v1)/4
then:
p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2
p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)
= 9.75×10^4 Pa
= 9.8×10^4 Pa
Therefore, the pressure in the wider section is 9.8×10^4 Pa
The spring constant is computed by:
F = kx
Where: F is the force applied in newtons (N)
k is the spring constant measured in newtons per meter (N/m); and
x is the distance the spring is stretched (m)
and
F = mg
Where: F is the force pulling objects in the direction of the Earth.
m is the mass of the object.
g is the acceleration due to gravity;
So plugging our values in the formula:
F = mg
= (1.8) (9.81) = 17.658N
k =
F/x = 17.658 /0.09 = 196.2 N/meter
