D - tertiary consumer
This is because it is the farther up to food chain.
Answer:
node
Explanation:
on the graph node is higher than antinode
so it can get or hear loud sounds faster
The answer is letter B. XD
<span>In this problem, we need to solve for Bubba’s mass. To do this, we let A be the area of the raft and set the weight of the displaced fluid with the raft alone as ρwAd1g and ρwAd2g with the person on the raft, </span>where ρw is the density of water, d1 = 7cm, and d2= 8.4 cm. Set the weight of displaced fluid equal to the weight of the floating objects to eliminate A and ρw then solve for m.
<span>ρwAd1g = Mg</span>
ρw<span>Ad2g = (M + m) g</span>
<span>d2∕d1 = (M + m)/g</span>
m = [(d2<span>∕d1)-1] M = [(8.4 cm/7.0 cm) - 1] (600 kg) =120 kg</span>
This means that Bubba’s mass is 120 kg.
Answer:
#See solution for details.
Explanation:
1.
Tools:
.
:Calculate the speed of the wave using the time,
it takes to travel along the rope. Rope's length,
is measured using the meter stick.
-Attach one end of rope to a wall or post, shake from the unfixed end to generate a pulse. Measure the the time it takes for the pulse to reach the wall once it starts traveling using the stopwatch.
-Speed of the pulse can then be obtained as:
: Apply force of known value to the rope then use the following relation equation to find the speed of a pulse that travels on the rope.
-Use the measuring stick and measuring scale to determine 
values of the rope then obtain 
.
-Use the force measuring constant to determine 
. These values can the be substituted in to obtain 
