[r] =6
Solve for r by simplifying both sides of the equation, then isolating the variable.
<em> </em>I hope this makes sense
Charge will decreases.
A parallel plate capacitor when it is fully charged to voltage V is given as:
C = Q/V
The capacitance of parallel plate capacitor with two plates of Area A separated by distance d and no dielectric material between plates is
C = ε₀ A /d
since from above equation it shows C is proportional to Q and also C is inversely proportional to distance d.
So, ATQ when d increases C will decrease which in result decreases charge on the capacitor.
Thus, Charge will decrease.
Learn more about capacitance here:
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Explanation:
It is given that,
Average power per unit mass generated by Lance, 

(a) Distance to cover race, 
Average speed of the person, v = 11 m/s
If t is the time taken to cover the race.


t = 14545.46 s
Let W is the work done. The relation between the work done and the power is given by :



W = 7090911.75 J
(b) Since, 
So, in 7090911.75 J, 
W = 1694.01 J
Hence, this is the required solution.
Answer:

Explanation:
initial velocity
magnitude of velocity, v = 12 m/s
angle made of velocity with negative x-axis,θ = 60°
We need to calculate x- component of v

velocity is in negative x-direction, v = -12 m/s
now,



Hence, the velocity x-component is equal to -6 m/s.
Answer:
Explanation:
radius of gyration of wheel k then
k² = r²/2
r² = 2 k²
r = √2 k
= 1.414 x .3 m
r = .4242 m
Moment of inertia of wheel
= mass x radius of gyration ²
= 25 x .3 x .3
= 2.25 kg m²
Friction force acting on it ( sliding )
= μmg , μ being coefficient of kinetic friction
This friction force will create linear acceleration in forward direction
Acceleration produced
= μg
= .6 x 9.8
= 5.88 m / s ²
This will also rotate the wheel , angular acceleration being
linear acceleration / radius
= 5.88 /.4242
= 13.86 radian / s²