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iragen [17]
3 years ago
5

¿Qué distancia recorrió un ciclista durante 6 minutos si su rapidez era de 11.11 m/s?

Physics
1 answer:
aalyn [17]3 years ago
5 0

Answer:

noooooo di por lo menos de que tema es que tipo de tema es division multiplicscion diii

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PtichkaEL [24]

All of that fluff at the beginning is interesting, but completely irrelevant
to the question.  The question is just asking for the mass of an object
that weighs 3.6N on Earth.

                           Weight = (mass) x (acceleration of gravity)

                              3.6N = (mass) x (9.8 m/s²)

Divide each side
by  9.8 m/s :           Mass = 3.6N / 9.8 m/s² = <em>0.367 kilogram</em> (rounded)


7 0
3 years ago
How do the different forms of potential energy depend on an object's position or chemical composition?
devlian [24]
It depends on the objects chemical composition.
6 0
3 years ago
A person's prescription for bifocals is -0.25 diopter for distant vision and +2.50 diopters for near vision, the near vision bei
Darina [25.2K]

Answer:

net power is + 2.25 D

Explanation:

Given data

distance vision = -0.25 D

near vision = + 2.50 D

to find out

net power

solution

we have given a person lens power for near is - 0.25 diopter and lens power for near power is  +2.50 diopter so

net power is sum of both the power vision

so

net power = distance + near power

put both value we get net power

net power = ( -0.25 D) + ( + 2.50 D)

net power = + 2.25 D

so net power is + 2.25 D

6 0
3 years ago
Even if there were some friction on the ice, it is still possible to use conservation of momentum to solve this problem, but you
hjlf

The problem referred to in this question is missing and it is;

Two hockey pucks of identical mass are on a flat, horizontal ice hockey rink. The red puck is motionless; the blue puck is moving at 2.5 m/s to the left. It collides with the motionless red puck. The pucks have a mass of 15 g. After the collision, the red puck is moving at 2.5 m/s, to the left. What is the final velocity of the blue puck?

Answer:

The condition is that p_f - p_i which is the change in momentum will not be equal to zero but equal to the impulse (Ft).

Explanation:

In the problem described, by inspection, we can say that since there is no friction, we have a closed system and thus momentum is conserved.

Since momentum is conserved, we can say that;

Initial momentum(p_i) = final momentum(p_f)

Now, in this question we are told that some friction wants to be introduced on the ice and it's possible to still use conservation of momentum.

From impulse - momentum theory, we know that;

Impulse = change in momentum

Impulse is zero when no force is acting on the ice and we have; 0 = p_f - p_i

This will yield initial momentum = final momentum.

Now, since a force is applied, we know that impulse is; J = F × t

Thus;

Ft = p_f - p_i

Where F is the force due to friction.

Thus, the condition is that p_f - p_i will not be equal to zero

6 0
3 years ago
Potassium is a crucial element for the healthy operation of the human
Dovator [93]
The second one if it’s on edge
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3 years ago
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