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iragen [17]
3 years ago
5

¿Qué distancia recorrió un ciclista durante 6 minutos si su rapidez era de 11.11 m/s?

Physics
1 answer:
aalyn [17]3 years ago
5 0

Answer:

noooooo di por lo menos de que tema es que tipo de tema es division multiplicscion diii

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40 POINTS!!
Mademuasel [1]

Answer:

1 put the black can in the temperature thing.

2.put the silver can well put water in it and leave it out side for a while.

3.Then you can be the judge of witch one will have a larger increase.

hope this helps :)

happy to help any time:)

Explanation:

3 0
3 years ago
Read 2 more answers
Experts, ACE, Genius... can anybody calculate for the Reactions at supports A and B please? Will give brainliest! Given: fb = 30
dybincka [34]

Answer:

Support at Cy = 1.3 x 10³ k-N

Support at Ay = 200 k-N

Explanation:

given:

fb = 300 k-N/m

fc = 100 k-N/m

D = 300 k-N

L ab = 6 m

L bc = 6 m

L cd = 6 m

To get the reaction A or C.

take summation of moment either A or C.

<em><u>Support Cy:</u></em>

∑ M at Ay = 0

      (( x1 * F ) + ( D * Lab ) + ( D * L bc + D * L cd )

Cy = -------------------------------------------------------------------

                                      ( L ab + L bc )

Cy = 1.3 x 10³ k-N

<em><u>Support Ay:</u></em>

Since ∑ F = 0,           A + C - F - D = 0

                                   A = F  + D - C

                                  Ay = 200 k-N

4 0
3 years ago
In a parallel circuit, if bulb #2 were to blow out, bulb #1 would stay lit or go out?
valkas [14]
Vhychhguuhkxkgxjgzkg
8 0
3 years ago
Steam types of<br> forces in<br> nature
max2010maxim [7]

Answer:

Gravity, Weak, Electromagnetic and Strong.

7 0
3 years ago
A furlong is an old british unit of length equal to 0.125 mi, derived from the length of a furrow in an acre of ploughed land. a
castortr0y [4]

The speed of light is: c = 3x10^8 m/s <span>

or 

c = 186,000,000 miles/sec = 1.86x10^8 mi/s 

1 furlong = 0.125 mile 

1 fortnight = 2 weeks(7d/wk)(24h/d)(3600s/h) 
= 1209600s = 1.2096x10^6 s 

Therefore, 

c =1.86x10^8 mi/s(1furl/0.125mi)(1.2096x10^6s/fort) 

<span>c = 18x10^14 furlong/fortnight = 18x10^8 Mfurlong/fortnight</span></span>

4 0
3 years ago
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