2. For one hour, you travel east in your car covering 100 km .Then travel south 100 km in 2 hours. You would tell your friends t
1 answer:
Answer:
Explanation:
Average velocity is change in position over the change in time. You have to take the directions into account. 100km east and then 100km south. That forms a right triangle, so you can use Pythagorean's theorem to find the hypotenuse which would be the displacement from his initial position:
Now take the displacement and divide it by the time it took to do the trip, 3 hours:
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Answer:
w = 0.943 rad / s
Explanation:
For this problem we can use the law of conservation of angular momentum
Starting point. With the mouse in the center
L₀ = I w₀
Where The moment of inertia (I) of a rod that rotates at one end is
I = 1/3 M L²
Final point. When the mouse is at the end of the rod
= I w + m L² w
As the system is formed by the rod and the mouse, the forces during the movement are internal, therefore the angular momentum is conserved
L₀ = L_{f}
I w₀ = (I + m L²) w
w = I / I + m L²) w₀
We substitute the moment of inertia
w = 1/3 M L² / (1/3 M + m) L² w₀
w = 1 / 3M / (M / 3 + m) w₀
We substitute the values
w = 1/3 / (1/3 + 0.02) w₀
w = 0.943 w₀
To finish the calculation the initial angular velocity value is needed, if we assume that this value is w₀ = 1 rad / s
w = 0.943 rad / s
Answer:
The maximum height of ball 2 is 4 times that of ball 1
Explanation:
We can find the maximum height of each ball by using the following suvat equation:
where
v is the final velocity
u is the initial velocity
is the acceleration of gravity (we take upward as positive direction)
s is the displacement
At the maximum height, s = h and v = 0 (the final velocity is zero), so re-arranging the equation:
The first ball is thrown with initial velocity , so it reaches a maximum height of
(the quantity will be positive, since g is negative)
The second ball is thrown with initial velocity
so it will reach a maximum height of
So, its maximum height will be 4 times the maximum height reached by ball 1.