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3 years ago

If the man is on the moon, where the acceleration due to gravity is gm = 5.30 ft/s2, determine his weight in pounds.

1 answer:

5 0

I am taking the average weight of the man into account here, which is 137 lbs.

We divide 5.30ft/s^2 by 32.2 ft/s^2, which is the acceleration due to gravity here on our planet and multiply the answer with the given weight (In this case, the weight of an average man since no value was stated in the question)

(5.30ft/s^2 ÷ 32.2 ft/s^2) 137 lbs = 22.55 lbs

He would weigh 22.55 lbs on the moon.

Hope this helps!

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On the surface of the earth the weight of an object is 200 lb. Determine the height of the

siniylev [52]

Answer:

The height of the object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

We need to calculate the value of $Gmm_{e}$

Using formula of gravitational force

$F=\dfrac{Gmm_{e}}{r^2}$

Put the value into the formula

$200=\dfrac{Gmm_{e}}{(3958.756)^2}$

$200\times(3958.756)^2=Gmm_{e}$

$Gmm_{e}=3.134\times10^{9}$

We need to calculate the height of the object

Using formula of gravitational force

$F=\dfrac{Gmm_{e}}{r^2}$

Put the value into the formula

$125=\dfrac{200\times(3958.756)^2}{r^2}$

$r^2=\dfrac{200\times(3958.756)^2}{125}$

$r^2=25074798.5$

$r=\sqrt{25074798.5}$

$r=5007.4\ miles$

Hence. The height of the object is 5007.4 miles.

7 0

3 years ago

what is the valure of work done on an objectwhen a 50newton force moves it 15 metrs in thesame dirction as the force

Snowcat [4.5K]

50 *15=750
work is force time distance times angle between both vectors
here the angle is 0.

5 0

4 years ago

Jacob is traveling at 5.00 m/s North. Jacob throws a ball with a velocity of 5.00 m/s South. Jacob throws the ball from a height

Nataly [62]

Answer:t=0.54 s

Explanation:

Given

Jacob is traveling 5 m/s in North direction

Jacob throw a ball with a in south direction with a velocity of 5 m/s

Ball is thrown in opposite direction of motion of car therefore it seems as if it is dropped from car as its net horizontal velocity is 5-5=0

Time taken by ball to reach ground

$s=ut+\frac{gt^2}{2}$

$1.45=0+\frac{9.81\times t^2}{2}$

$t^2=frac{2\times 1.45}{9.81}$

t=0.54 s

Motion of ball will be straight line

3 0

3 years ago

An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.200 rev/s . The magnitude

blagie [28]

Answer:

(A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

Explanation:

Given that,

Initial angular velocity = 0.200 rev/s

Angular acceleration = 0.883 rev/s²

Diameter = 0.760 m

Time = 0.204 s

(A). We need to calculate the angular velocity of fan

Using equation of angular motion

$\omega_{f}=\omega_{i}+\alpha t$

Put the value into the formula

$\omega_{f}=0.200+0.883\times0.204$

$\omega_{f}=0.380\ rev/s$

(B). We need to calculate the number of revolution

Using formula of angular displacement

$\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2$

Put the value into the formula

$\theta=0.200\times0.204+\dfrac{1}{2}\times0.883\times(0.204)^2$

$\theta=0.059\ rad$

(C). We need to calculate the tangential speed of the blade

Using formula of speed

$v=\dfrac{d}{2}\omega_{f}$

Put the value into the formula

$v=\dfrac{0.760}{2}\times0.380\times2\pi$

$v=0.907\ m/s$

(D). We need to calculate the tangential acceleration of the blade

Using formula of tangential acceleration

$a_{t}=\alpha r$

Put the value into the formula

$a_{t}=0.883\times0.38\times2\pi$

$a_{t}=2.10\ m/s^2$

Hence, (A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

3 0

3 years ago

A worker does 25 J of work lifting a bucket, then sets the bucket back down in the same place. What is the total net work done o

Sloan [31]

Answer:

b. 0 J

Explanation:

Work is the cross product of force and displacement. Since the bucket has 0 displacement, the net work is 0 J.

6 0

3 years ago

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