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2 years ago

If the man is on the moon, where the acceleration due to gravity is gm = 5.30 ft/s2, determine his weight in pounds.

1 answer:

5 0

I am taking the average weight of the man into account here, which is 137 lbs.

We divide 5.30ft/s^2 by 32.2 ft/s^2, which is the acceleration due to gravity here on our planet and multiply the answer with the given weight (In this case, the weight of an average man since no value was stated in the question)

(5.30ft/s^2 ÷ 32.2 ft/s^2) 137 lbs = 22.55 lbs

He would weigh 22.55 lbs on the moon.

Hope this helps!

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nirvana33 [79]

Answer:

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2 years ago

What is angular velocity

butalik [34]

Answer:

angular velocity(ω) is the rate change of angular displacement.

ω=θ/t and it SI unit is rad/s

Explanation:

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2 years ago

Two objects are dropped from rest from the same height. Object A falls through a distance Da and during a time t, and object B f

stiv31 [10]

Answer:

Da=(1/4)Db

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

When s = Da, t = t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times t^2\\\Rightarrow Da=\frac{1}{2}at^2$

When s = Db, t = 2t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times (2t)^2\\\Rightarrow Db=\frac{1}{2}a4t^2$

Dividing the two equations

$\frac{Da}{Db}=\frac{\frac{1}{2}at^2}{\frac{1}{2}a4t^2}=\frac{1}{4}\\\Rightarrow \frac{Da}{Db}=\frac{1}{4}\\\Rightarrow Da=\frac{1}{4}Db$

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3 years ago

A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a rope that goes over an ideal pulley. If the masses are

irga5000 [103]

Answer:

The time taken will be 0.553 seconds.

Explanation:

We should start off by finding the force exerted by the rope on the 3kg weight in this case.

Weight of 5kg mass = 5 * 9.81 = 49.05 N

Weight of 3kg mass = 3 * 9.81 = 29.43 N

The force acting upward on the 3kg mass will equal the weight of the 5kg mass. Thus the resultant force acting on the 3kg mass is:

Total force = 49.05 - 29.43 = 19.62 N (upwards)

We can now find the acceleration:

F = m * a

19.62 = 3 * a

a = 6.54 m/s^2

We now use the following equation of motion to get the time taken to travel 1 meter:

$s=u*t+\frac{1}{2} (a*t^2)$

$1=0*t+\frac{1}{2} (6.54*t^2)$

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3 years ago

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aliina [53]

Answer:

529 Hz

Explanation:

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2 years ago