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Artyom0805 [142]
3 years ago
14

Zinc phosphide, Zn3P2, is often used as a rat poison. Phosphorus has 5 valence electrons. How many valence electrons does each z

inc atom lose?
Chemistry
2 answers:
Helen [10]3 years ago
8 0
The choices that should have accompanied this question were:
A. 1 
<span>B. 2 </span>
<span>C. 3 </span>
<span>D. 4 
</span>
My answer is B. 2.
Below is an explanation, I found while doing the research.

<span>Phosphate needs 3 electrons each totaling 6 electrons so each zinc will need to give up 2 electrons.

Phosphate wants to imitate the electron configuration of Argon because noble configurations are the most stable. With P getting the extra electrons the valence shell will be 3s2 3p6, which is the same as Argon. Without the extra electrons, the P valence shell looks like this 3s2 3p3, now you can see why each phosphorus wants 3 more electrons, that will make it 3s2 3p6, just like Argon.</span>
ryzh [129]3 years ago
6 0

Answer:

The correct answer is two valence electrons.

Explanation:

Hello! We will answer this!

As the phosphorus has 5 valence electrons, in the first layer it has 2, so the ones it combines are 3. In total there are 6 negative phosphorus charges because they are two phosphorus atoms. The number of Zinc atoms is 3 so to balance the loads, you have to have +2 so that in total there are 6 charges.

The correct answer is two valence electrons.

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A 125g sample of a mixture of salt and sand contains 12% salt.
natka813 [3]
12 % salt is present in 125 g mixture of salt and sand.
Keep in mind that the total percentage is always 100 %
Therefore, if 12 % is the salt, remaining 88 % must be
sand.
a. The amount of mixture is 125 q. Here, 12 % of 125 is
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4 0
2 years ago
You need to prepare 150 mL of 0.1 M solution of silver chloride. How much silver chloride is required?
Rudiy27

Answer:

amount of silver chloride required is 0.015 moles or 2.1504 g

Explanation:

0.1M AgCL means 0.1mol/dm³ or 0.1mol/L

1L = 1000mL

if 0.1mol of AgCl is contained in 1000mL of solution

then x will be contained in 150mL of solution

cross multiply to find x

x = (0.1*150)/1000

x= 0.015 moles

moles of silver chloride present in 150 mL of solution is 0.15 moles

To convert this to grams, simply multiply this value by the molar mass of silver chloride

molar mass of silver chloride AgCl =107.86 + 35.5

                                                     =143.36 g/mol

mass of AgCl = moles *molar mass

                       =0.015*143.36

                        =2.1504g

                        =

4 0
3 years ago
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