The molecular formula of methylpropan-1-ol is C4H10O, so the complete combustion equation is: C4H10O + 6O2 --> 4CO2 + 5H2O. This mean to completely combust 1.0mol of methylpropan-1-ol, 6 mol of O2 is required. Molar mass of O2 is 32 g/mol, so 32g/mol x 6mol = 192 g of O2 is required. At room temperature and pressure, the density of O2 is 1.3315 g/L (this can be obtained by density of gas = P/RT). So the volume of O2 = mass/density = 192g/1.3315(g/L) = 144 L = 144 dm3. The answer is B.
Answer:
D) 0.86 M
Explanation:
Given that:
The rate constant, k = 6.7×10⁻⁴ s⁻¹
Initial concentration [A₀] = 1.33 M
Time = 644 s
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
is the concentration at time t
So,
![[A_t]=1.33\times e^{-6.7\times 10^{-4}\times 644}](https://tex.z-dn.net/?f=%5BA_t%5D%3D1.33%5Ctimes%20e%5E%7B-6.7%5Ctimes%2010%5E%7B-4%7D%5Ctimes%20644%7D)
![[A_t]=0.86 M](https://tex.z-dn.net/?f=%5BA_t%5D%3D0.86%20M)
<h2>Example of Physical change </h2>
Ice forming and then melting back into water are an example of physical change because the nature of water is liquid. Yet when it freezes then it becomes into solid form. The water which is liquid then freezes to form ice form which is as a solid which is also a physical change.
If we see that when ice which is frozen and in solid form starts to melt by heat then it converts into water which is liquid form. This indicates that water freezes to form ice means liquid to solid therefore its shape changes which is a physical change. When ice melts it becomes solid to liquid it also changes shape and subsequently takes a physical change.
Answer: They're called Periods
Answer:
will be the speed in 
Explanation:
This is a unit conversion problem.
To solve it, we need the equivalences between km and ft, ft and mi and hr and s.
The equivalences are :

If
then

The trick is to multiply by one the speed given until to convert it in mi/s units

Notice that km,ft,hr and min have been cancelled.
Be careful of the fraction order.
Multiply by ft/km is different that multiply by km/ft