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tigry1 [53]
3 years ago
13

Draw a sodium formate molecule. The structure has been supplied here for you to copy. To add formal charges, click the button be

low (which will turn yellow when activated) before clicking on the molecule. Draw sodium formate by placing atoms on the grid and connecting them with bonds. Include all lone-pair electrons. View available hint(s)

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.

Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).

Nomenclature:

                       In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.

Name of Formate:

                             Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.

E.g.

                    HCOOH (formic acid)    →     HCOO⁻ (formate)  +  H⁺

                H₃CCOOH (acetic acid)     →      H₃CCOO⁻ (acetate)  +  H⁺

Formal Charges:

                           Formal charges are calculated using following formula,

          F.C  =  [# of Valence e⁻] - [e⁻ in lone pairs + 1/2 # of bonding electrons]

For Oxygen:

                    F.C  =  [6] - [6 + 2/2]

                    F.C  =  [6] - [6 + 1]

                    F.C  =  6 - 7

                    F.C  =  -1

For Sodium:

                    F.C  =  [1] - [0 + 0/2]

                    F.C  =  [1] - [0]

                    F.C  =  1 - 0

                    F.C  =  +1

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The reaction is:

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Na^+  and CO_3^2 - are the spectator ions.

<h3><u>Explanation:</u></h3>

The reactants in the reaction is sodium acetate and ammonium carbonate. They form the soluble molecule sodium carbonate and slightly soluble ammonium acetate. This is a double displacement reaction.

Spectator ions in the reaction are those ions which are present in the reaction but they actually don't take part in the reaction that's happening and they remain same before and after the reaction. In this reaction, the spectator ions are sodium and carbonate which remain in ionized form in the solution before and after the reaction.

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4 years ago
A sample of gas has a volume of 526 mL at 346 mmHg and 35.0°C. Determine the moles of gas.​
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Answer:

The moles of gas is 0.009474 moles.

Explanation:

Given that,

Volume = 526 mL

Pressure = 346 mmHg

Temperature = 35.0°C

We need to calculate the moles of gas

Using formula of ideal gas

n=\dfrac{PV}{RT}

Where, P = pressure

V = volume

R = gas constant

T = temperature

Put the value into the formula

n=\dfrac{\dfrac{346}{760}\times0.526}{0.08206\times(35+273)}

n=0.009474\ moles

Hence, The moles of gas is 0.009474 moles.

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3 years ago
The pressure of nitrogen gas at 35°C is changed from 0.89 atm to 4.3 atm. What will be its final temperature in Kelvin?
Alja [10]

Answer: The final temperature in Kelvin is 1488

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=0.89atm\\T_1=35^0C=(35+273)K=308K\\P_2=4.3atm\\T_2=?

Putting values in above equation, we get:

\frac{0.89}{308}=\frac{4.3}{T_2}\\\\T_2=1488K

Hence, the final temperature in Kelvin is 1488

8 0
3 years ago
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