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3 years ago

Which is the appropriate unit of measurement for pitch? decibel mel joule watt

2 answers:

5 0

The mel scale is used when people deal with the perception of pitch. The mel scale is about the apprehend spacing of the frequencies.

1kHz is used as an implication point and then the mel scale is derived from there only.

Mel unit uses the apprehend pitch difference in a linear way as compared to hertz, thus Mel unit is used as the appropriate unit measurement for pitch.

Therefore, option (B) is correct.

Travka [436]3 years ago

4 0

The answer would be mel

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Oksanka [162]

X-axis=time
y-axis=distance (position)

slope=y-axis / x-axis=distance / time=velocity.

answer: d) slope

6 0

3 years ago

If water is leaking from a certain tank at a constant rate, is it leaking at a rate that is greater than 12 liters per hour?(1 l

Margarita [4]

Answer:

Yes it is possible because 3.33 is greater than 2.

Explanation:

Given that,

1 liter = 1000 milliliters

Suppose water is leaking from the tank at a rate that is greater than 2 milliliters per second.

We need to change the unit in ml/s

$12 lit/hr=\dfrac{12000}{3600}$

$12 lit/hr=3.33\ ml/s$

Hence, Yes it is possible because 3.33 is greater than 2.

5 0

3 years ago

At an outdoor market, a bunch of bananas attached to the bottom of a vertical spring of force constant 16.0 N/m is set into osci

aksik [14]

Answer:

Explanation:

Answer:

4.53 kg

Explanation:

spring constant, K = 16 N/m

Amplitude, A = 20 cm = 0.2 m

Maximum speed, v = 37.6 cm/s = 0.376 m/s

The formula for maximum speed is given by

v = ωA

where, ω is the angular frequency

0.376 = ω x 0.2

ω = 1.88 rad/s

$\omega =\sqrt{\frac{K}{m}}$

$m = \frac{K}{\omega ^{2}}$

$m = \frac{16}{1.88 ^{2}}$

m = 4.53 kg

Thus, the mass of banana bunch is 4.53 kg.

8 0

3 years ago

According to the ideal gas law, a 1.074 mol sample of oxygen gas in a 1.746 L container at 267.6 K should exert a pressure of 13

luda_lava [24]

Answer:

% differ 1.72%

Explanation:

given data:

P_ideal = 13.51 atm

n = 1.074 mol

V = 1.746 L

T = 267.6 K

According to ideal gas law we have

$(P+ \frac{n^2 *a}{v^2}) (V - nb) = nRT$

$(P+ (\frac{1.074^2 *1.360}{1.746^2})) (1.746 - 1.074*3.183*10^{-2}) = 1.074*0.0821*267.6$

(P+0.514)(1.711) = 23.59

P_v = 13.276 atm

% differ $= \frac{ P_I - P_v}{P_I} *100$

$= \frac{13.51 - 13.27}{13.51} *100$

= 1.72%

3 0

4 years ago

If a car travels 400m in 20 seconds how fast is it going? 20 m/s

scoundrel [369]

Answer:

20m/s

Explanation:

Speed = distance / time

Speed = 400/20

Speed = 20

5 0

3 years ago