Characteristics sa Ancient art
1 answer:
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Answer:
Explanation:
The capacitance of the parallel-plate capacitor is given by
where
ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity
k = 3.00 is the dielectric constant
is the area of the plates
d = 9.00 mm = 0.009 m is the separation between the plates
Substituting,
Now we can calculate the energy of the capacitor, given by:
where
C is the capacitance
V = 15.0 V is the potential difference
Substituting,
Answer:
The energy stored in the capacitor quadruples its original value.
Explanation:
The energy stored in a capacitor is given by the equation
where
C is the capacitance
V is the voltage across the plates
The capacitance, C, depends only on the properties of the capacitor, so it does not change when the voltage applied is changed.
Instead, in this problem the voltage applied is doubled:
V' = 2V
So the new energy stored is
so, the energy stored has quadrupled.