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fiasKO [112]
3 years ago
15

Review Multiple-Concept Example 7 in this chapter as an aid in solving this problem. In a fast-pitch softball game the pitcher i

s impressive to watch, as she delivers a pitch by rapidly whirling her arm around so that the ball in her hand moves in a circle. In one instance, the radius of the circle is 0.602 m. At one point on this circle, the ball has an angular acceleration of 64.1 rad/s2 and an angular speed of 13.0 rad/s. (a) Find the magnitude of the total acceleration (centripetal plus tangential) of the ball. (b) Determine the angle of the total acceleration relative to the radial direction.
Physics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

108.8 m /s

θ = 21°

Explanation:

Centripetal acceleration = ω² R

=( 13 )² x .602

= 101.74 m/s²

tangential acceleration a_t = angular acceleration x R

= 64.1 x .602

= 38.58 m /s²

Total acceleration R

R² = ( 101.74 )² + ( 38.58 )²

R = 108.8 m /s

angle required be θ

Tanθ = tangential accn  / radial accn

= 38.58  / 101.74

θ = 21°

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A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th
vladimir1956 [14]

Answer:

Force, F=2.27\times 10^4\ N

Explanation:

Given that,

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Distance, d = 4.35 cm = 0.0435 m

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The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

F.d=\dfrac{1}{2}m(v^2-u^2)

Finally, it stops, v = 0

F.d=-\dfrac{1}{2}m(u^2)

F=\dfrac{-mu^2}{2d}

F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}

F = -22713.92 N

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7 0
3 years ago
If the time of impact in a collision is extended by 3 times, by hour much is
vodomira [7]

Answer:

The force of the impact would be smaller

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If the force is big then the time would be small (2500N of Force = 10 seconds)

If the force is small then the time would be big (250N of Force = 50 seconds)

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The resistance of a wire depends upon the material's resistivity and the length and cross‑sectional area of the wire. What will
andriy [413]

Answer:

R' = 4R

The resistance will become 4 times the initial value.

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The resistance of a wire at room temperature, is given by the following formula:

R = ρL/A   ----------- equation 1

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R = Resistance of wire

ρ = resistivity of the material

L = Length of wire

A = Cross-sectional area of wire

Now, if the length (L) is multiplied by 4, then resistance will become:

R' = ρ(4L)/A

R' = 4 (ρL/A)

using equation 1:

<u>R' = 4R</u>

<u>The resistance will become 4 times the initial value.</u>

6 0
3 years ago
On the surface of the earth the weight of an object is 200 lb. Determine the height of the
siniylev [52]

Answer:

The height of the  object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

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Put the value into the formula

200=\dfrac{Gmm_{e}}{(3958.756)^2}

200\times(3958.756)^2=Gmm_{e}

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We need to calculate the height of the  object

Using formula of gravitational force

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Put the value into the formula

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r^2=\dfrac{200\times(3958.756)^2}{125}

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r=\sqrt{25074798.5}

r=5007.4\ miles

Hence. The height of the  object is 5007.4 miles.

7 0
3 years ago
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