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lara [203]
3 years ago
14

n an ecosystem, energy that flows to tertiary consumers ultimately originates from the sun. Please select the best answer from t

he choices provided T F
Physics
2 answers:
telo118 [61]3 years ago
7 0

Answer: True

A food chain is a linear sequence of supply or transfer of food and energy when one organism is consumed by another in an ecosystem. The energy being transferred to different organisms can be studied on the basis of energy pyramid in which energy is distributed among organisms in subsequent trophic levels. At the base level, the producers or plants obtain energy from sun which they utilize to produce food or biomass energy. The biomass energy from plants is transferred to primary consumers or herbivores. The primary consumers are eaten up by secondary consumers. The secondary consumers are eaten up by tertiary consumers.

This can be concluded that the initial source of energy being distributed to all trophic levels in food chain is originated from sun. Therefore, the statement "In an ecosystem, energy that flows to tertiary consumers ultimately originates from the sun" is true.

Alenkasestr [34]3 years ago
6 0
The correct answer for the question that is being presented above is this one: "TRUE." <span>N an ecosystem, energy that flows to tertiary consumers ultimately originates from the sun. This statement is true. The sun is a source of energy most especially in plants.</span>
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Problems related to radiation. (a) The temperature of the Sun’s photosphere is 5700 K. Assume it is a blackbody. What is the pea
sineoko [7]

Answer:

a) λ = 5,084 10⁻⁷ m , b)  P = 3.63 10²⁶ W , c)  P = 5.8 10²⁷ W and d)  λ = 2.54 10⁻⁷ m

Explanation:

a) The maximum emission of the sun can be calculated using the Win equation

     λ T = 2,898 10⁻³ m.K

     λ = 2,898 10⁻³ / T

     λ = 2,898 10⁻³ / 5700

     λ = 5,084 10⁻⁷ m

     λ = 5,084 10⁻⁷ m (1 10⁹ nm / 1m) =

     λ = 5,084 10² nm = 508.4 nm

      photon in the visible range

b) The emission of the Sun, is described by the Stefan equation

     P = σ A e T⁴

Where σ is the Stefan-Boltzmann constant that vslue is  5,670 10-8 W/m²K⁴, A area of ​​the Sun, and e the emissivity that for a perfect black body is 1

In order to use this equation, we must calculate the area of ​​the sun, we consider it a perfect sphere

      r = 695,000 km (1000m / 1 km) = 6.95 10⁸ m

Area of ​​a sphere

     A = 4π R²

     A = 4π (6.95 10⁸8)²

     A = 6.07 10¹⁸ m²

     P = 5,670 10⁻⁸ 6.07 10¹⁸  1  5700⁴

     P = 3.63 10²⁶ W

c) The new temperature is double the previous one

    T = 2 To

Let's substitute in the formula and calculate

     P = σ A e (2To)⁴

     P = σ A e T⁴ 2⁴

     Po = σ A e T4 = 3.63 10 26 W

   

    P = 16 Po

    P= 16 (3.63 10²⁶)

    P = 5.8 10²⁷ W

d) Let's calculate the explicit value of the temperature and use the Win equation

    T = 2 5700

    T = 11400K

    λ = 2,898 10⁻³ / 11400

    λ = 2.54 10⁻⁷ m

    λ = 2.54 10²nm = 254 nm

photon in the UV range

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Answer:

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Answer:

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Explanation:

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vazorg [7]

Answer:

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Explanation:

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