Question

What are the roots of f(x) = x2 – 48? –48 and 48 –24 and 24

Answer 1

The roots of
  f(x) = x² - 48
are found by solving
  x² - 48 = 0
  x² = 48 . . . . . . add 48
  x = ±√48 . . . . take the square root

The roots of f(x) are -4√3 and +4√3.

Answer 2

Answer:  The roots of the given quadratic function are

$x=4\sqrt3,~-4\sqrt3.$

Step-by-step explanation:  We are given to find the roots of the following quadratic function:

$f(x)=x^2-48.$

The roots of the above quadratic function will be given by equating the expression for f(x) to zero.

The roots of the above quadratic function f(x) is given by

$f(x)=0\\\\\Rightarrow x^2-48=0\\\\\Rightarrow x^2=48\\\\\Rightarrow x=\pm\sqrt{48}~~~~~~~~\textup{[taking square root on both sides]}\\\\\Rightarrow x=\pm4\sqrt3.$

Thus, the roots of the given quadratic function are

$x=4\sqrt3,~-4\sqrt3.$