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Goryan [66]
3 years ago
12

Part a what happens to these physical properties as the strength of intermolecular forces increases? drag each item to the appro

priate bin. hints helpreset melting pointvapor pressureboiling pointviscositysurface tension increase decrease
Chemistry
2 answers:
Marysya12 [62]3 years ago
6 0
<h2>Strength when Intermolecular Forces Increase </h2>

When the strength of intermolecular forces increases then boiling point, melting point, viscosity, surface tension also increases and vapor pressure decreases. With the increase of intermolecular forces B.P, M.P, viscosity and surface tension increases because strong intermolecular forces require more energy to break.

For this purpose energy is provided in the form of heat energy. Therefore, the ones which have stronger bonds will have a higher B.P, M.P, viscosity and surface tension. When the intermolecular forces are strong then the substances are tightly held together so the vapor pressure will be low and it will be difficult to vaporize.


bearhunter [10]3 years ago
4 0
1. Melting point is the temperature at which the solid turns to liquid. In order to reach this point, the intermolecular forces of the solid must be broken so that it would incorporate the molecular arrangement of a liquid.<em> So, the stronger the intermolecular forces, the greater the energy which consequently leads to higher melting points.</em>

2. Vapor pressure is the pressure exerted by the gas above its solid or liquid substance. It is closely related to volatility, which is the ability of the substance to convert from liquid to gas at a certain temperature. <em>The stronger the intermolecular force, the less volatile the substance is which is manifested in increasing vapor pressure.</em>

3. Boiling point has the same concept as melting point, but the change is from liquid to gas. <em>So, the stronger the intermolecular forces, the greater the energy which consequently leads to higher boiling points.</em>

4. Viscosity is the ease of fluidity. Solids, which have stronger intermolecular forces are not viscous at all. <em>So, the stronger the intermolecular forces, the viscosity decreases.</em>

5. Surface tension is the force the substance exerts near its surface or interface. <em>The stronger the intermolecular force, the stronger the surface tension. </em>
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Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit
vfiekz [6]

Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For H_2SO_4:-  

Mass of H_2SO_4 = 196 g

Molar mass of H_2SO_4 = 98 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{196\ g}{98\ g/mol}

Moles\ of\ Sulfuric\ acid= 2\ mol

According to the given reaction:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,  

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

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7 0
2 years ago
onsider the reversible dissolution of lead(II) chloride. P b C l 2 ( s ) − ⇀ ↽ − P b 2 + ( a q ) + 2 C l − ( a q ) PbClX2(s)↽−−⇀
Sveta_85 [38]

Answer:

9.34x10^-4

Explanation:

Step 1:

The balanced equation for the reaction.

PbCl2( s ) <=> Pb^2+(aq) + 2Cl^−(aq)

Step 2:

Data obtained from the question:

Mass of PbCl2 = 0.2393 g

Volume = 50mL

concentration of Pb^2+, [Pb^2+] = 0.0159 M

Concentration of Cl^-, [Cl^-] = 0.0318 M

Equilibrium constant, Kc =?

Step 3:

Determination of the number of mole PbCl2.

The number of mole of PbCl2 can be obtained as follow:

Molar Mass of PbCl2 = 207 + (35.5x2) = 278g/mol

Mass of PbCl2 = 0.2393 g

Number of mole =Mass /Molar Mass

Number of mole of PbCl2 = 0.2393/278 = 8.61x10^-4 mole

Step 4:

Determination of Molarity of PbCl2.

At this stage we shall obtain the molarity of PbCl2. This is shown below:

Mole of PbCl2 = 8.61x10^-4 mole

Volume = 50mL = 50/1000 = 0.05L

Molarity of PbCl2 =?

Molarity = mole /Volume

Molarity of PbCl2 = 8.61x10^-4/0.05

Molarity of PbCl2 = 0.01722 M

Step 5:

Determination of the equilibrium constant Kc.

PbCl2( s ) <=> Pb^2+(aq) + 2Cl^−(aq)

The equilibrium constant Kc for the equation above is given by:

Kc = [Pb^2+] [Cl^-]^2 / [PbCl2]

[Pb^2+] = 0.0159 M

[Cl^-] = 0.0318 M

[PbCl2] = 0.01722 M

Kc =?

Kc = [Pb^2+] [Cl^-]^2 / [PbCl2]

Kc = 0.0159 x (0.0318)^2/ 0.01722

Kc = 9.34x10^-4

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