Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that .
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Wassup
Steps:
1. Draw a line connecting the point to the center of the rectangle
2. Then construct a perpendicular bisector to the line drawn in step 1
3. Place the compass on the midpoint of the line, adjust its length to reach the end point, and draw an arc across the circle
4. Where the arc crosses the circle will be the tangent points. So connect the endpoint to the tangent point
Hope the picture helps you too
Answer:
I'm assuming you want the distance between the two point
EF =
GH =
Step-by-step explanation: