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stellarik [79]
3 years ago
15

What will change the velocity of a periodic wave?

Physics
1 answer:
Fantom [35]3 years ago
8 0
<span>it will be changed by changing the medium of the wave</span>
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A cylinder 0.170 m in diameter rotates in a lathe at 530 rpm . what is the tangential speed of the surface of the cylinder?
Ad libitum [116K]
Diameter = 0.170 meter
Circumference = 0.170 π meters

530 rpm = 530 circumferences / minute

               =  (530 x 0.170 π meters) / minute

               =      283.06 meter.minute

               =        4.72 meters/second
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3 years ago
the refractive index is the blank of the speed of light in a medium to the speed of light in a vacuum
andrew11 [14]

Answer:ratio

Explanation:

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3 years ago
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Question 13 (1 point)
KonstantinChe [14]

Answer:

Reflective clothing. So vehicles can see them and stuff.

3 0
2 years ago
The electric current in a copper wire is composed of what
Tanzania [10]

Answer:

A copper wire current consists of electrons appropriately called conduction electrons.

Explanation:

This answer came from quizlet.com. I hope that this helps you and good luck!

8 0
3 years ago
Light of wavelength 436.1 nm falls on two slits spaced 0.31 mm apart. What is the required distance from the slits to the screen
kakasveta [241]

Answer:

The correct answer is "4.26 m".

Explanation:

Given:

Wavelength,

\lambda = 436.1 \ nm

or,

  =436.1\times 10^{-9} \ m

Distance,

d = 0.31 \ mm

or,

  =0.31\times 10^{-3} \ m

Distance between the 1st and 2nd dark fringes,

(y_2-y_1) = 6\times 10^{-3} \ m

As we know,

⇒ \frac{d}{L} (y_2-y_1) = \lambda

or,

⇒ L=\frac{d(y_2-y_1)}{\lambda}

By substituting the values, we get

       =\frac{0.31\times 6\times 10^{-6}}{436.1\times 10^{-9}}

       =\frac{0.31\times 6\times 10^3}{436.1}

       =\frac{1860}{436.1}

       =4.26 \ m

3 0
3 years ago
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