The maximum speed of the object under simple harmonic motion is 0.786 m/s.
The given parameters:
- Position of the particle, y = 0.5m sin(πt/2)
<h3>Wave equation for
simple harmonic motion;</h3>
y = A sin(ωt + Ф)
where;
- A is the amplitude = 0.5 m
- ω is the angular speed = π/2
The maximum speed of the object is calculated as follows;
![V_{max} = A \omega\\\\V_{max} = 0.5 \times \frac{\pi}{2} = \frac{\pi}{4} \ m/s = 0.786 \ m/s](https://tex.z-dn.net/?f=V_%7Bmax%7D%20%3D%20A%20%5Comega%5C%5C%5C%5CV_%7Bmax%7D%20%3D%200.5%20%5Ctimes%20%5Cfrac%7B%5Cpi%7D%7B2%7D%20%3D%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%5C%20m%2Fs%20%20%3D%200.786%20%5C%20m%2Fs)
Thus, the maximum speed of the object under simple harmonic motion is 0.786 m/s.
Learn more about simple harmonic motion here: brainly.com/question/17315536
<span>The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the "Radio waves"
So, option B is your answer
Hope this helps!
</span>
Answer:
v (speed) = S / t = 4 * 400 m / (6 * 60 sec) = 4.4 m/s
The average velocity is zero because there is no net vector displacement.
Velocity is a vector quantity. A vector quantity has both a magnitude and a direction. Speed only has a magnitude, but no direction. Velocity has both.
Answer:28m/s
Explanation:I got one point so yeah hope this help