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Ksenya-84 [330]
4 years ago
9

Sam is pulling a box up to the second story of his apartment via a string. The box weighs 16.5 kg and starts from rest on the gr

ound. Sam is pulling so that the velocity of the box is increasing by 2.6 m/s every second.
How long until the box reaches a height of 13.2 m?
Physics
1 answer:
Katyanochek1 [597]4 years ago
8 0

Answer:

Weight (mass) = 16.5 kg

velocity = 0 m/a

acceleration =2.6 m/s^2

displacement = 13.2m

now,

acceleration = velocity/ time

2.6 = 0 / t

t = o / 2.6

t = o

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2 years ago
Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha
GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

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