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4 years ago

What is an astronomer? Answer in the simpliest way please.

Physics

1 answer:

Sphinxa [80]4 years ago

8 0

They would be an expert in astronomy
astronomy:the branch of science that deals with celestial objects

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Fish are considered a renewable resource. However, some scientists believe that Earth's oceans are running out of economically v

ch4aika [34]

The most likely answer will be B. Overfishing is still a large issue today, and it can really ruin a habitat. =)

3 0

4 years ago

Read 2 more answers

All objects in our solar system orbit the Sun. How is the movement of planets like

seraphim [82]

Answer:

planets move in elliptical orbit.

Explanation:

this is because planets are formed closer to the sun while the comets are formed further.

4 0

3 years ago

Monochromatic light of wavelength λ=620nm from a distant source passes through a slit 0.450 mm wide. The diffraction pattern is

Elan Coil [88]

Answer:

The intensity of light from the 1mm from the central maximu is $I = 0.822I_o$

Explanation:

From the question we are told that

The wavelength is $\lambda = 620 nm = 620 *10^{-9}m$

The width of the slit is $w = 0.450mm = \frac{0.45}{1000} = 0.45*10^{-3} m$

The distance from the screen is $D = 3.00m$

The intensity at the central maximum is $I_o$

The distance from the central maximum is $d_1 = 1.00mm = \frac{1}{1000} = 1.0*10^{-3}m$

Let z be the the distance of a point with intensity I from central maximum

Then we can represent this intensity as

$I = I_o [\frac{sin [\frac{\pi * w * sin (\theta )}{\lambda} ]}{\frac{\pi * w * sin (\theta )}{\lambda } } ]^2$

Now the relationship between D and z can be represented using the SOHCAHTOA rule i.e

$sin \theta = \frac{z}{D}$

if the angle between the the light at z and the central maximum is small

Then $sin \theta = \theta$

Which implies that

$\theta = \frac{z}{D}$

substituting this into the equation for the intensity

$I = I_o [\frac{sin [\frac{\pi w}{\lambda} \cdot \frac{z}{D} ]}{\frac{\pi w z}{\lambda D\frac{x}{y} } } ]$

given that $z =1mm = 1*10^{-3}m$

We have that

$I = I_o [\frac{sin[\frac{3.142 * 0.45*10^{-3}}{(620 *10^{-9})} \cdot \frac{1*10^{-3}}{3} ]}{\frac{3.142 * 0.45*10^{-3}*1*10^{-3} }{620*10^{-9} *3} } ]^2$

$=I_o [\frac{sin(0.760)}{0.760}] ^2$

$I = 0.822I_o$

4 0

3 years ago

According to Newtons first law, an object in motion will stay in motion unles.....

Juli2301 [7.4K]

acted upon a outside unbalance force.

6 0

4 years ago

PLEASE I NEED THIS QUICKLY

saveliy_v [14]

Answer:

should be A

Explanation:

4 0

3 years ago