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sasho [114]
3 years ago
5

Which of the following correctly describe electric field lines?

Physics
2 answers:
Anastasy [175]3 years ago
7 0

Explanation:

The imaginary lines that shows the direction of electric field are called electric field lines. The direction of electric field lines are from positive charge to the negative charge.

Two electric field lines can never ever intersect, if they do so there would be two direction of electric field at that point, which is not possible.

If the electric field lines are very to each other, then it indicates the stronger electric field. The electric field lines is unaffected by the nature of charged particle that created them.

Hence, the correct options are :

(A) They never cross

(B) Field lines that are close together indicate a stronger electric field

(C) They don't affect the charge that created them.

Xelga [282]3 years ago
6 0

-- Electric field lines DO never cross.  <em>(A) </em>

-- Electric field lines that are close together DO indicate a stronger electric field. <em>(B) </em>

-- Electric field lines DO not affect the charge that created them.  <em>(C)</em>

-- Electric field lines DON'T begin on north poles and end on south poles.  North and South "poles" are the way we talk about magnets, not electric charges.

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Which factor/s affect the amount of energy stored in a magnetic field?
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Answer:

The answer is I

Explanation:

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"On a movie set, an alien spacecraft is to be lifted to a height of 32.0 m for use in a scene. The 260.0-kg spacecraft is attach
Lisa [10]

Answer:

<em>The time interval required to lift the spacecraft to this specified height is 123.94 seconds</em>

Explanation:

Height through which the spacecraft is to be lifted = 32.0 m

Mass of the spacecraft = 260.0 kg

Four crew member each pull with a power of 135 W

18.0% of the mechanical energy is lost to friction.

work done in this situation is proportional to the mechanical energy used to move the spacecraft up

work done = (weight of spacecraft) x (the height through which it is lifted)

but the weight of spacecraft = mg

where m is the mass,

and g is acceleration due to gravity 9.81 m/s

weight of spacecraft = 260 x 9.81 = 2550.6 N

work done on the space craft = weight x height

==> work = 2550.6 x 32 = 81619.2 J

this is equal to the mechanical energy delivered to the system

18.0% of this mechanical energy delivered to the pulley is lost to friction.

this means that

0.18 x 81619.2  = <em>14691.456 J  </em> is lost to friction.

Total useful mechanical energy =  81619.2 J - 14691.456 J = 66927.74<em> J</em>

Total power delivered by the crew to do this work = 135 x 4 = 540 W

But we know tat power is the rate at which work is done i.e

P = \frac{w}{t}

where p is the power

where w is the useful work done

t is the time taken to do this work

imputing values, we'll have

540 = 66927.74/t

t = 66927.74/540

time taken t = <em>123.94 seconds</em>

8 0
3 years ago
What is the kinetic energy of a 2122 kg car parked in a parking lot?
Sedbober [7]

Answer:

There is no kinetic energy.

Explanation:

Since K=1/2mv^2 where m=2122kg and v=0, clearly the car has no kinetic energy as multiplying by 0 results in 0. If the car were moving, there would be kinetic energy.

3 0
3 years ago
What three forces contribute to the rise of water in a capillary tube?
Leviafan [203]
These three forces are cohesive force, adhesive force and surface tension. The cohesive and adhesive forces are opposite of each other. While cohesive force is the intermolecular bonding between like molecules, the adhesive force is the intermolecular force between unlike molecules. Surface tension is perceived to be the force exerted by the liquid near the surface of the water. Together, these forces bring about an increase in liquid height when a very small tube is placed on a wide surface liquid.
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3 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You have a stopped pipe of adjustable length clo
faltersainse [42]

Answer:

Length of pipe = 0.057 meter

Explanation:

Speed of a transverse wave on a string

v = \sqrt{\frac{F}{\mu} }

where F is the tension in string and \mu is the mass per unit length

Thus,

\mu = \frac{m}{L}

Substituting the given values we get -

\mu = \frac{7.25 * 10^{-3}}{0.62}\\mu = 0.0117 \frac{Kg}{m}

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v = \sqrt{\frac{4510}{0.0117} } \\v = 620.86 \frac{m}{s}

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f = \frac{nv}{2L}

Substituting the given values, we get -

f = \frac{3 * 620.86}{2 * 0.62} \\f = 1502.08

Length of pipe

L = \frac{nv}{4 f}

Substituting the given values we get

n = 1 for first harmonic wave

L = \frac{344* 1}{4*1502.08} \\L = 0.057

Length of pipe = 0.057 meter

5 0
4 years ago
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