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4 years ago

A 10-Newton object displaces 12 Newtons of water. Will this object sink of float?

Chemistry

2 answers:

timurjin [86]4 years ago

6 0

This object would float

Gennadij [26K]4 years ago

4 0

Answer: The object will float.

Explanation:

Balanced force is defined as the force that gets cancelled out when equal forces are acting in the opposite direction. The net force on the system comes out to be 0.

Unbalanced force is defined as the force that does not get cancelled out because unequal forces act on the system in opposite direction. The motion of the object is in the direction of net force.

According to the question:

Object is exerting a downward force of 10 N on the water and water is exerting an upward force of 12 N on water.

As, the upward force by water is more than the downward force by object. So, the object will float on the surface of water.

If the downward force by the object is been more than the upward force, the object will sink.

Hence, the object will float.

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True or false: different substances are made up of different types of atoms

Degger [83]

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3 years ago

Read 2 more answers

) B5H9(l) is a colorless liquid that will explode when exposed to oxygen. How much heat is released when 0.211 mol of B5H9 react

Tom [10]

Answer: The amount of heat released when 0.211 moles of $B_5H_9(l)$ reacts is 554.8 kJ

Explanation:

The chemical equation for the reaction of $B_5H_9$ with oxygen gas follows:

$2B_5H_9(l)+12O_2(g)\rightarrow 5B_2O_3(s)+9H_2O(l)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(5\times \Delta H_f_{(B_2O_3(s))})+(9\times \Delta H_f_{(H_2O(l))})]-[(2\times \Delta H_f_{(B_5H_9(l))})+(12\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(H_2O(l))}=-285.4kJ/mol\\\Delta H_f_{(B_2O_3(s))}=-1272kJ/mol\\\Delta H_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-1272))+(9\times (-285.4))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H_{rxn}=-5259kJ$

To calculate the amount of heat released for the given amount of $B_5H_9(l)$ , we use unitary method, we get:

When 2 moles of $B_5H_9(l)$ reacts, the amount of heat released is 5259 kJ

So, when 0.211 moles of $B_5H_9(l)$ will react, the amount of heat released will be = $\frac{5259}{2}\times 0.211=554.8kJ$

Hence, the amount of heat released when 0.211 moles of $B_5H_9(l)$ reacts is 554.8 kJ

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3 years ago

Plants respire only during the day

disa [49]

False, they respire all the time including nighttime

3 0

3 years ago

Help Pls thnk you !!!!!!!!!!!!!!!!!!!!!!!!!

uysha [10]

The answer is double displacement is the answer

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3 years ago

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Natalka [10]

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3 years ago