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3 years ago

A 10-Newton object displaces 12 Newtons of water. Will this object sink of float?

Chemistry

2 answers:

timurjin [86]3 years ago

6 0

This object would float

Gennadij [26K]3 years ago

4 0

<u>Answer:</u> The object will float.

<u>Explanation:</u>

Balanced force is defined as the force that gets cancelled out when equal forces are acting in the opposite direction. The net force on the system comes out to be 0.

Unbalanced force is defined as the force that does not get cancelled out because unequal forces act on the system in opposite direction. The motion of the object is in the direction of net force.

According to the question:

Object is exerting a downward force of 10 N on the water and water is exerting an upward force of 12 N on water.

As, the upward force by water is more than the downward force by object. So, the object will float on the surface of water.

If the downward force by the object is been more than the upward force, the object will sink.

Hence, the object will float.

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Hello! I hope this helps

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3 years ago

What intermolecular force attracts two non polar molecules to each other

Salsk061 [2.6K]

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2 years ago

What factors do you think should be considered in selecting a metal to use to reclaim copper? Which factor do you think is the m

Lana71 [14]

Answer:

Aluminum

Explanation:

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7 0

2 years ago

The feed to a batch process contains equimolar quantities of nitrogen and methane. write an expression for the kilograms of nitr

timama [110]

1) number of moles of N2 = n/2

2) Number of moles of CH4 = n/2

3) Total number of moles of the mixture = n/2 + n/2 = n

4) Kg of N2

mass in grams = number of moles * molar mass

molar mass of N2 = 2 * 14.0 g/mol = 28 g/mol

=> mass of N2 in grams = (n/2) * 28 = 14n

mass of N2 in Kg = mass of N2 in grams * [1 kg / 1000g] = 14n/1000 kg = 0.014n kg

Answer: mass of N2 in kg = 0.014n kg

3 0

3 years ago

If 2,035 cal of heat is added to a 500.0 g sample of water at 35.0°C, what is the final

Lynna [10]

Answer:

39.1 °C

Explanation:

Recall the equation for specific heat:

$q=mc \Delta T\\$

Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.

You should know that the specific heat of water is 1 cal/g/C.

Using the information in the question:

$2035=500(1)(T-35)\\2035=500T-17500\\500T=19535\\T=39.07$

The final temperature is about 39.1 °C.

5 0

3 years ago