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USPshnik [31]
3 years ago
6

After a hormone enters the bloodstream, it is transported throughout the body, but the hormone only affects certain cells. The r

eason only certain cells are affected is that the membranes of these cells have specific
Chemistry
1 answer:
USPshnik [31]3 years ago
5 0
The membranes have specific receptors, you're welcome :).
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In the lab you weigh out 76.02 g of Iron (Fe). How many moles of Iron do you have in the sample. (Your answer must have a unit..
son4ous [18]

Answer:

We have 1.361 moles in the sample

Explanation:

Mass of iron = 76.02g

Molar mass of iron = 55.845 g/ mole ( This we can find in the periodic table, and menas that 1 mole of iron has a mass of 55.845 g).

To calculate the number of moles we will use following formula:

moles (n) = mass / molar mass

moles iron = 76.02g / 55.845 g/ mole

moles iron = 1.36127 moles

To use the correct number of significant digits we use the following rule for multiplication and division :

⇒ the number with the least number of significant figures decides the number of significant digits.

⇒76.02 has 4 digits ( 2 after the comma) and 55.845 has 5 digits (3 after the comma).

⇒ this means 1.361 moles

We have 1.361 moles in the sample

3 0
3 years ago
Can someone help me please.
Vika [28.1K]

Answer:

ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

Explanation:

ccccccccccccccccccccccccccc

4 0
3 years ago
An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0
Vlad [161]

Answer:

1.2 atm

Explanation:

Given data

  • Volume of the gas in the tank (V₁): 200.0 L
  • Pressure of ethylene gas in the tank (P₁): ?
  • Volume of the gas in the torch (V₂): 300 L
  • Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm

3 0
3 years ago
a car is traveling at a speed of 55 mph the speed increased to 75 mph if the time needed to hange its speed is 4 seconds whats t
Savatey [412]

v = 75 mph = 33.52 m/s

u = 55 mph = 24.58 m/s

t = 4 sec

acceleration = v-u/t

= 33.52-24.58/4

= 8.94/4

= 2.235 m/s

6 0
3 years ago
Is elemental phosphorus dull or high luster?
Ugo [173]
Each element<span> can usually be classified as a metal or a non-metal based on their ... They are usually </span>dull<span>and therefore show no metallic </span>luster<span> and they do not reflect ... </span>Dull<span>, Brittle solids; Little or no metallic </span>luster<span>; </span>High<span> ionization energies; </span>High<span> ...</span>
7 0
3 years ago
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