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loris [4]
3 years ago
11

Illustrate the x- and y-axes to show the reaction pathway and potential energy, in kilojoules. Ensure your energy intervals are

appropriate for the data.
Plot the enthalpy values of the reactants, products, and transition state using three horizontal dotted lines across the graph for each.

Draw the energy curve from the reactants line to the transition state and curve the line back down to the energy of the products. Label the reactants, products, and transition state.

Illustrate double-headed arrows to represent both the total change in enthalpy (ΔH) and the activation energy (Ea).

Calculate the total change in enthalpy and the activation energy using the energy values provided for each reaction. Record those values below the graph.

Make sure correct units are included.

I know this is a lot, so I'm giving more points than I ever have. Thank you!!!

Chemistry
1 answer:
Rufina [12.5K]3 years ago
6 0

Answer:

Enthalpy of a reaction = P - R  

Synthesis: ΔH = 25 kJ - (-30 kJ) = 55 kJ  

Single Replacement: ΔH = 30kJ - 65 kJ = -35 kJ  

Double Replacement: ΔH = 60 kJ - 10 kJ = 50 kJ

Explanation:

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7 0
3 years ago
A sample was prepared by mixing 18. ml of 3.00 x 10^-3 m crystal violet (cv) with 2.00 ml of 0.250 m naoh. calculate the resulti
Aleks [24]

Answer : The resulting concentrations of CV and NaOH are 0.0027 M and 0.025 M respectively.

Explanation :

Step 1 : Find moles of crystal violet and NaOH.

The molarity formula is

Molarity = \frac{mol}{L}

Molarity of crystal violet = 3.00 \times 10^{-3} = \frac{mol (CrystalViolet)}{L}

The volume of crystal violet solution is 18 mL which is 0.018 L.

Moles of crystal violet = 3.00 \times 10^{-3} \times 0.018 = 5.4 \times 10^{-5}

Moles of crystal violet = 5.4 x 10⁻⁵

Moles of NaOH = Molarity \times L = 0.250 \times 0.00200 = 5.00 \times 10^{-4}

Moles of NaOH = 5.00 x 10⁻⁴

Step 2 : Find total volume of the solution

The total volume of the solution after mixing NaOH and crystal violet is

0.018 L + 0.00200 = 0.020 L

Step 3 : Use molarity formula to find final concentrations

Molarity of crystal violet = \frac{mol(CrystalViolet)}{Total Volume(L) } = \frac{5.4 \times 10^{-5}}{0.020} = 2.7 \times 10^{-3}

Final concentration of CV = 0.0027 M

Molarity of NaOH= \frac{mol(NaOH)}{Total Volume(L) } = \frac{5.00 \times 10^{-4}}{0.020} = 0.025 \times 10^{-3}

NaOH is a strong base and dissociates completely as follows.

NaOH (aq) \rightarrow Na^{+} (aq) + OH^{-} (aq)

The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.

Concentration of OH⁻ = 0.025 M

8 0
3 years ago
Explain why the quantum number set (3, 2, 3, -½) is not possible for an electron in an atom
Triss [41]
Ok the ML (the 3rd number) is not legit because the ML value can only be from -L to L (the second value)
7 0
3 years ago
A scientific ________ must have a control, so that the variables that could affect the out come is reduced. A:experiment B:concl
Lostsunrise [7]

Answer:

A.experiment

Explanation:

hope this helps

4 0
3 years ago
What volume of oxygen at STP is requieres for the complete combustion of 100.50 mL of C2H2
malfutka [58]

The volume of oxygen at STP required would be 252.0 mL.

<h3>Stoichiometic problem</h3>

The equation for the complete combustion of C2H2 is as below:

2C_2H_2 + 5O_2 --- > 4CO_2 + 2H_2O

The mole ratio of C2H2 to O2 is 2:5.

1 mole of a gas at STP is 22.4 L.

At STP, 100.50 mL of C2H2 will be:

                 100.50 x 1/22400 = 0.0045 mole

Equivalent mole of O2 according to the balanced equation = 5/2 x 0.0045 = 0.01125 moles

0.01125 moles of O2 at STP = 0.01125 x 22400 = 252.0 mL

Thus, 252.0 mL of O2 gas will be required at STP.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

7 0
1 year ago
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