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loris [4]
3 years ago
11

Illustrate the x- and y-axes to show the reaction pathway and potential energy, in kilojoules. Ensure your energy intervals are

appropriate for the data.
Plot the enthalpy values of the reactants, products, and transition state using three horizontal dotted lines across the graph for each.

Draw the energy curve from the reactants line to the transition state and curve the line back down to the energy of the products. Label the reactants, products, and transition state.

Illustrate double-headed arrows to represent both the total change in enthalpy (ΔH) and the activation energy (Ea).

Calculate the total change in enthalpy and the activation energy using the energy values provided for each reaction. Record those values below the graph.

Make sure correct units are included.

I know this is a lot, so I'm giving more points than I ever have. Thank you!!!

Chemistry
1 answer:
Rufina [12.5K]3 years ago
6 0

Answer:

Enthalpy of a reaction = P - R  

Synthesis: ΔH = 25 kJ - (-30 kJ) = 55 kJ  

Single Replacement: ΔH = 30kJ - 65 kJ = -35 kJ  

Double Replacement: ΔH = 60 kJ - 10 kJ = 50 kJ

Explanation:

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irina1246 [14]
The number of Zn particles (atoms of Zn ) in the first sample, and Zn ions are going to be the same, 
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6 0
3 years ago
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snow_lady [41]

Answer:Light bounces off of the mirror and then appears to come from behind the mirror.

Explanation:Plane mirrors form images that are virtual, upright and the same size and shape as the object it is reflecting.

When rays of light from the object hits a plane mirror they bounces off the mirror,that is they undergo reflection, and appear to originate from behind the mirror, resulting to the formation of a virtual image.

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4 0
2 years ago
Untitled Section
ipn [44]

Answer:

B.

Explanation:

Hope this helps.

7 0
3 years ago
A chemist dissolves 0.096 g of CuSO4 · 5 H2O in water and dilutes the solution to the mark in a 500-mL volumetric flask. A 6-mL
scoray [572]

Answer:

(A) 4.616 * 10⁻⁶ M

(B) 0.576 mg CuSO₄·5H₂O

Explanation:

  • The molar weight of CuSO₄·5H₂O is:

63.55 + 32 + 16*4 + 5*(2+16) = 249.55 g/mol

  • The molarity of the first solution is:

(0.096 gCuSO₄·5H₂O ÷ 249.55 g/mol) / (0.5 L) = 3.847 * 10⁻⁴ M

The molarity of CuSO₄·5H₂O is the same as the molarity of just CuSO₄.

  • Now we use the dilution factor in order to calculate the molarity in the second solution:

(A) 3.847 * 10⁻⁴ M * 6mL/500mL = 4.616 * 10⁻⁶ M

To answer (B), we can calculate the moles of CuSO₄·5H₂O contained in 500 mL of a solution with a concentration of 4.616 * 10⁻⁶ M:

  • 4.616 * 10⁻⁶ M * 500 mL = 2.308 * 10⁻³ mmol CuSO₄·5H₂O
  • 2.308 * 10⁻³ mmol CuSO₄·5H₂O * 249.55 mg/mmol = 0.576 mg CuSO₄·5H₂O
5 0
3 years ago
Please am confused and need help​
alex41 [277]

Answer:

1.  C

2.  C

3.  A

4.  C

5.  True

6.  C

Explanation:

1. C  The answer is conduction because the heat was transferred through direct contact.

2. C  The answer convection because the heat was transferred through a medium (liquid/gas).

3. A  The answer is conduction because the heat was transferred through direct contact.

4. C  The answer is radiation because the heat was transferred through thermal emission.

5. True.  This is because the air that is warmed rises, causing the cool air to replace it.  You can picture it like the scenario in question 2.

6. C  

3 0
3 years ago
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