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hodyreva [135]
3 years ago
8

Write a brief desperation for each of newtons three laws

Chemistry
1 answer:
Greeley [361]3 years ago
4 0
1st law: law of inertia, an object will remain stationary unless a force acts upon it.
2nd law: law of acceleration: the momentum experienced by an object is proportional to the size and direction of the force.
3rd law: law of action and reaction: for every action there is an equal and opposite reaction.
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How many square centimeters are in an area of 8.50 inch^2
Paha777 [63]

Explanation:

Given parameters:

  Dimension = 8.5in²

we are to convert from in² to cm²

 in² = in x in

 cm² = cm x cm

   1 in = 2.54cm

Using dimensional analysis;

   8.5in² x \frac{2.54cm}{1in}  x \frac{2.54cm}{1in}

        =  54.84cm²

We solved this problem using dimensional analysis where we multiplied the unit with 1.

learn more:

Conversion brainly.com/question/555814

#learnwithBrainly

5 0
3 years ago
I AM GIVING AWAY 80 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
dangina [55]

Answer:

thank you so much!!!!!!!!!!!!

6 0
3 years ago
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The filling of which orbital is represented by the transition metals in period 4?
Sindrei [870]

Answer: 3d

Explantion:

1) Period 4 contains the elements with atomic numbers 19 through 36.

2) The elements with atomic numbers 19 (K) and 20 (Ca) fill the orbital 4s.

3) After that, as Aufbau's rule may help you to remember, the energy of the orbitals 3d is lower than the energy of the orbtitals 4p. So, the element 21 (Sc) start fillind the orbital 3d.

There are ten 3d orbitals, so the elements 21 through 30 fill the 3d orbitals.

Those elements, called transition metals are: Sc, Ti, V, Cr, Mn, Fe, Co, Ni, Cu, and Zn.

When the 3d orbitals are full, the next elements in the same period 4, fill the six 4p orbitals.

3 0
3 years ago
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What heat is liberated in the formation of 10.0 grams of sulfur hexafluoride, SF6, from the elements sulfur and fluorine?
tensa zangetsu [6.8K]

Answer:

Q=-76.7kJ

Explanation:

Hello,

In this case, for such formation of sulfur hexafluoride, the standard enthalpy of formation is -1220.47 kJ/mol (data extracted from NIST database). Next, we compute the moles in 10.0 grams of sulfur hexafluoride as shown below:

n_{SF_6}=10.0gSF_6*\frac{1molSF_6}{146.06 gSF_6}=0.0685mol

Next, for the given energy, we compute the total heat that is liberated:

Q=-1220.47\frac{kJ}{mol}*0.0685 mol\\\\Q=-76.7kJ

Finally, we conclude such symbol has sense since negative heat is related with liberated heat.

Best regards.

8 0
3 years ago
During the light-independent reaction, carbon dioxide is fixed by adding it to a A. 2-carbon compound B. 3-carbon compound C. 4-
Scrat [10]
During the light independent reaction, carbon dioxide is fixed by adding it to a <span>5-carbon compound</span>
8 0
3 years ago
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