☃️ Chemical formulae ➝
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
Atomic weight of elements:
Ca = 40
C = 12
O = 16
❍ Molecular weight of
= 40 + 12 + 3 × 16
= 52 + 48
= 100 g/mol
❍ Given weight: 10 g
Then, no. of moles,
⇛ No. of moles = 10 g / 100 g mol‐¹
⇛ No. of moles = 0.1 moles
☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>
<u>━━━━━━━━━━━━━━━━━━━━</u>
Answer: The standard cell potential (E∘) for the reaction is -0.121 V
Explanation:
The reaction is:
Relation between standard Gibbs free energy and equilibrium constant follows:
where,
= Standard Gibbs free energy = ?
R = Gas constant =
T = temperature = 298 K
K= equilibrium constant =
Putting values in above equation, we get:
To calculate standard Gibbs free energy, we use the equation:
Where,
n = number of electrons transferred = 1
F = Faradays constant = 96500 C
= standard cell potential = ?
Putting values in above equation, we get:
Thus standard cell potential (E∘) for the reaction is -0.121 V