The answer is the first one because the sodium is the first element of the third row, thus 3s^1
Answer:
Explanation:
Equation of the reaction:
O3(g) + NO(g) ⟶ O2(g) + NO2(g)
From the Rate Law:
R = k[O3][NO]
The order of NO is 1 and that of O3 is also 1, therefore order of reaction = 1 + 1
= 2
Given :
Concentration of O3, [O3] = 7.0×10^-4M
Concentration of NO, [NO] = 5.0×10^-5M
Rate constant, k = 3.0 × 10^6M^-1s^-1
R = 3.0×10^6 × 7.0×10^-4 × 5.0×10^-5
= 0.105 M/s
Answer:
480.40 g.
Explanation:
- According to the balanced equation:
<em>2 SO₂(g) + O₂(g) → 2 SO₃(g),</em>
it is clear that 2.0 moles of SO₂ react with 1.0 mole of oxygen to produce 2.0 moles of SO₃.
- We can get the no. of moles of SO₃ produced:
∵ 2.0 moles of SO₂ produce → 2.0 moles of SO₃, from the stichiometry.
∴ 6.0 moles of SO₂ produce → 6.0 moles of SO₃.
- Then, we can get the mass of the produced 6.0 moles of SO₃ using the relation:
<em>mass = no. of moles x molar mass of SO₃</em> = (6.0 moles)(80.066 g/mol) = <em>480.396 g ≅ 480.40 g.</em>