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Elden [556K]
3 years ago
6

If the specific heat of water is 4.186 kJ/kg∙°C, how much heat is required to increase the temperature of 1.2 kg of water from 2

3 °C to 39 °C?
Chemistry
1 answer:
PIT_PIT [208]3 years ago
4 0
This<span> will require'' </span>266.9kJ''<span> of heat energy 

</span>

To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material, <span>m</span>

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Answer:

P_2=1.90atm

Explanation:

Hello!

In this case, according to the ideal gas equation ratio for two states:

\frac{P_1V_1}{P_2V_2} =\frac{n_1RT_1}{n_2RT_2}

Whereas both n and R are cancelled out as they don't change, we obtain:

\frac{P_1V_1}{P_2V_2} =\frac{T_1}{T_2}

Thus, by solving for the final pressure, we obtain:

\frac{P_2V_2}{P_1V_1} =\frac{T_2}{T_1}\\\\P_2=\frac{T_2P_1V_1}{V_2T_1}

Now, since initial conditions are 1.00 atm, 273.15 K and 17 L and final temperature and volume are 94 + 273 = 367 K and 12 L respectively, the resulting pressure turns out to be:

P_2=\frac{367K*1.00atm*17L}{12L*273.15K}\\\\P_2=1.90atm

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A scientist has 0.12 miles of a gas at a pressure of 4.06 kPa and a volume of 14 liters in an enclosed container. What is the te
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Answer:

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Explanation:

P = 4.06kPa = 4.06×10³Pa

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T = ?

We need ideal gas equation to solve this question

From ideal gas equation,

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P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles

R = ideal gas constant

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