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Elden [556K]
3 years ago
6

If the specific heat of water is 4.186 kJ/kg∙°C, how much heat is required to increase the temperature of 1.2 kg of water from 2

3 °C to 39 °C?
Chemistry
1 answer:
PIT_PIT [208]3 years ago
4 0
This<span> will require'' </span>266.9kJ''<span> of heat energy 

</span>

To calculate the energy required to raise the temperature of any given substance, here's what you require:

The mass of the material, <span>m</span>

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The town in the video stressed using locally made goods instead of imported goods. How could using locally made goods lower CO2
ladessa [460]

Answer:

It reduces the need to import goods

Explanation:

When you buy locally, the products you buy don't come from far away, so they don't have to cross the country (or the ocean) by boat, plane or trucks to reach the market/store where you're buying, at least not from a long distance away.

The distance a vehicle travels, the less CO2 emissions it produces.

If the good you're buying is made/produced only an hour away, that's not much pollution produced compared as if the good has to come from a distant place spending days on highways to reach you.

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How many moles of gold are there in 14.2×1023 atoms of gold?
timofeeve [1]

Answer : The correct answer is 2.36 mol of gold

1 mole of any element have 6.022 x 10²³ number of atoms ( Avogadro's number).

So the formula relating mole and number of atoms is given as :

Mole = \frac{given number of atom }{ 6.022 * 10^2^3 atom}    * 1 mol

Plugging value in formula :

Mole = \frac{14.2 *10^2^3 }{6.022 x10^2^3}   * 1 mol

Mole of gold = 2.36 mol

4 0
3 years ago
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A brown dye has a percent composition of 62.41% C, 5.24% H, and 32.36% N by mass with a molar mass of 346.40 g/mol. Determine th
Fiesta28 [93]

The molecular formula : C₁₈H₁₈N₈

<h3>Further explanation</h3>

Given

62.41% C, 5.24% H, and 32.36% N

Required

The molecular formula

Solution

mol ratio

C : 62.41/12.0096 = 5.1967

H : 5.24/1.00784 = 5.1992

N : 32.36/14.0067 = 2.310

Divide by 2.310(smallest)

C : 5.1967/2.31=2.25

H : 5.1992/2.31 = 2.25

N : 2.31/2.31 = 1

Multiplied by 4

C : H : N = 9 : 9 : 4

The empirical formula : C₉H₉N₄

(C₉H₉N₄)n=346.40 g/mol

(12.0096 x 9 + 1.00784 x 9 + 14.0067 x 4)n=346.4

(108.0864+9.07056+56.0268)n=346.4

(173.184)n=346.4

n=2

<em>The molecular formula : C₁₈H₁₈N₈</em>

8 0
2 years ago
What is oxidized and what is reduced in this reaction?
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N is oxidized and O is reduced

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