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romanna [79]
3 years ago
5

What can you say about the reactants of photosynthesis and the products of cellular respiration? pls don't search this up on gòo

gle ​
Chemistry
1 answer:
KatRina [158]3 years ago
8 0

Answer: The products and reactants for photosynthesis are reversed in cellular respiration: The reactants of photosynthesis are carbon dioxide and water, which are the products of cellular respiration. The reactants of cellular respiration are oxygen and sugar, which are the products of photosynthesis.

Explanation:

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How many atoms would fit across a human hair? *
kow [346]

A typical human hair is about 1 million carbon-12 atoms JUST IN WIDTH.

4 0
3 years ago
Read 2 more answers
Based on the results you observed for the iodine test and Benedict’s test, is it better to detect enzyme activity by measuring t
dlinn [17]

Answer:

Is better use the Benedict's test by the increase in the amount of the products if the enzyme is a reductase

Explanation:

The Benedict's test works by the reaction of the reducing sugars with the ion cupric of the reactive. If the enzyme is a reductase (degrades polysaccharides into bi o monosaccharides), it should cut the polysaccharide bond and the products would react with the Benedict's cupric ion

I hope you undestand me

3 0
3 years ago
How many moles of hydrogen atoms are there in one mole of C6H12O2
zvonat [6]

In 1 molecule of the compound C₆H₁₂O₂ there are 12 moles of hydrogen atoms

<h3>Further explanation</h3>

Given

C₆H₁₂O₂ compound

Required

moles of Hydrogen

Solution

In a compound, there is a mole ratio of the constituent elements.

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

In the C₆H₁₂O₂ compound, there are 3 forming elements: C, H and O

The number of each element is indicated by its subscript

C: 6 moles

H = 12 moles

O = 2 moles

7 0
3 years ago
The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process
tensa zangetsu [6.8K]

Answer: a) 1.7\times 10^{-4}

b) 3.4\times 10^{-4}

Explanation:

The reaction is :

2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Rate = Rate of disappearance of N_2O_5 = Rate of appearance of NO_2

Rate =  -\frac{d[N_2O_5]}{2dt} = \frac{d[NO_2]}{4dt}

Rate of disappearance of N_2O_5 = \frac{\text {change in concentration}}{time} = \frac{0.100-0.066}{200-0}=1.7\times 10^{-4}

a) Rate of disappearance of N_2O_5 = -\frac{d[N_2O_5]}{2dt}

Rate of appearance of NO_2 = \frac{d[NO_2]}{4dt}

b) Rate of appearance of NO_2 =  \frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}

8 0
3 years ago
A stock phenolphthalein solution was prepared by dissolving 0.050 g in a total volume of 100.0 ml. You place one drop (0.050 ml)
devlian [24]

Answer:

the value of molar absorptivity is 229000 M^{-1} cm^{-1}

Explanation:

given data

phenol phthalein solution = 0.050 g

total volume = 100.0 ml

dilute = 100.0 ml

diluted sample = 0.18

solution

we get here concentration that is express as

concentration = ( mass of solute × 1000 ) ÷ ( molar mass of solute × volume of solution ) .............1

put here value

concentration = \frac{0.050\times 1000}{318.32\times 100}    

concentration = 0.00157 M

and here dillution equation is express as

c1 × v1 = c2 × v2   .................2

here c1 and c2 is initial and final concentration

and v1 and v2 is initial and final volume

put here value  

0.001571 × 0.050 = c2 × 100

c2 = 7.855 × 10^{-7} M

and

now we get molar by absorbance equation that is

A = E × C ×  l   ................3

here A is absorbance and E is molar and c is absorptivity and l is path length

put here value

0.18 = E × 7.855 × 10^{-7}  × 1

E = 229000 M^{-1} cm^{-1}

3 0
3 years ago
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