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DaniilM [7]
3 years ago
6

A car weighs 15,000 N, and its tires are inflated to a pressure of 190 kPa.How large is the area of the car's tires that are in

contact with the road?
Physics
2 answers:
marusya05 [52]3 years ago
8 0

Answer : A = 0.07895\ m^{2}

Explanation :

Given that,

Weight = 15000 N

Pressure = 190 kPa

We knows, pressure is defined as force acting per unit area.

In mathematical term

P = \dfrac{F}{A}\ Pascal

Now, the area of the car's tires that are in contact with the road is

A = \dfrac {1500\ N}{190\times10^{3}\ Pa}\ m^{2}

A = 0.07895\ m^{2}

Hence, this is the required solution.

Elan Coil [88]3 years ago
7 0
Pressure is the force applied perpendicular to a surface divided by the area of the surface. Therefore, from the given values, we can easily calculate the area by dividing the force to the pressure. We do as follows:

Area = F / P
Area = 15000 / 190000
Area = 0.0789 m^2

Hope this answers the question. Have a nice day.
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What is the mass of a large ship that has a momentum of 1.60x10^9 kg*m/s and is moving at a velocity of 10m/s?
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Answer:

160000000 kg.

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p=mv

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7 0
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When you're asked to calculate moments and torque, what's the main difference in calculation? Also what is a couple?
leva [86]

Answer:

a) Explanation below. b) Explanation below

Explanation:

Torque is defined as the product of a force by a radius, while momentum is defined as the product of force by a distance. Mathematically we would have

T = F * r

M = F * d

where:

T = torque = [N*m]

M = moment = [N*m]

F = force =[N]

d = distance [m]

r = radius [m]

Although they have the same units, the difference between them is the application. For the case of torque this is always applied in parts that are in rotation, such as the shafts of cars, the shafts of pumps, torque in gears and etc. While the moment can be applied to a body without the need for it to rotate.

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7 0
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Example No. 10
Alexxx [7]

The force constant of the spring is determined as 14,222.2 N/m.

<h3>Force constant of the spring</h3>

Apply the principle of conservation of energy,

K.E = U

where;

  • K.E kinetic energy of the elevator
  • U is elastic potential energy of the spring

¹/₂mv² = ¹/₂kx²

mv² = kx²

k = mv²/x²

Where;

  • m is mass of the elevator
  • v is speed
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k = (2000 x 8²)/(3²)

k = 14,222.2 N/m

Thus, the force constant of the spring is determined as 14,222.2 N/m.

Learn more about force constant here: brainly.com/question/1968517

#SPJ1

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