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DaniilM [7]
3 years ago
6

A car weighs 15,000 N, and its tires are inflated to a pressure of 190 kPa.How large is the area of the car's tires that are in

contact with the road?
Physics
2 answers:
marusya05 [52]3 years ago
8 0

Answer : A = 0.07895\ m^{2}

Explanation :

Given that,

Weight = 15000 N

Pressure = 190 kPa

We knows, pressure is defined as force acting per unit area.

In mathematical term

P = \dfrac{F}{A}\ Pascal

Now, the area of the car's tires that are in contact with the road is

A = \dfrac {1500\ N}{190\times10^{3}\ Pa}\ m^{2}

A = 0.07895\ m^{2}

Hence, this is the required solution.

Elan Coil [88]3 years ago
7 0
Pressure is the force applied perpendicular to a surface divided by the area of the surface. Therefore, from the given values, we can easily calculate the area by dividing the force to the pressure. We do as follows:

Area = F / P
Area = 15000 / 190000
Area = 0.0789 m^2

Hope this answers the question. Have a nice day.
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We can find the velocity of the ball 1 s after reaching its highest point by using again the equation:

a=\frac{v-u}{t}

where this time we have

a = g = -9.8 m/s^2 is the acceleration due to gravity, still negative

v  is the final velocity (1 s after reaching the highest point)

u = 0 is the initial velocity (at the highest point)

t = 1 s is the time interval

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and the negative sign means it points downward.

(e) -9.8 m/s

The change in velocity during the 1-s interval is given by

\Delta v = v -u

where here we have

v = -9.8 m/s is the final velocity (1 s after reaching the highest point)

u = 0 is the initial velocity (at the highest point)

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The change in velocity during the overall 2-s interval is given by

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where in this case we have:

v = -9.8 m/s is the final velocity (1 s after reaching the highest point)

u = +9.8 m/s is the initial velocity (1 s before reaching the highest point)

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\Delta v = -9.8 m/s - (+9.8 m/s)=-19.6 m/s

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There is always one force acting on the ball during the motion: the force of gravity, which is given by

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m is the mass of the ball

g = -9.8 m/s^2 is the acceleration due to gravity

According to Newton's second law, the resultant of the forces acting on the body is equal to the product of mass and acceleration (a), so

mg = ma

which means that the acceleration is

a= g = -9.8 m/s^2

and the negative sign means it points downward.

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