Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.
1 answer:
Answer:
gravitational force acting on the piano (piano's weight)
force of Chadwick on the piano
force of the floor on the piano (normal force)
Explanation:
Figure is missing: found it in attachment.
In the figure, we notice that the piano is accelerating along the horizontal direction: this means that there is a net force acting along this direction. This force is prodiced by Chadwick, and it acts in the same direction as the acceleration, so one force is:
force of Chadwick on the piano
Also, every object on Earth experencies the force of gravity, which is also called weight. The weight of the piano acts downward, so a second force is:
gravitational force acting on the piano (piano's weight)
Finally, we notice that the piano is in equilibrium along the vertical direction (no acceleration): this is because there is another force acting opposite to the piano's weight (and with equal magnitude), and this force is the normal force exerted by the floor on the piano:
force of the floor on the piano (normal force)
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Answer:
The answer is below
Explanation:
Newton's law of gravity states that the force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The law is expressed by the formula:
The masses and distances for this question is in common units, Therefore the result would be in ratios
a) 4 MEarth / 2 MSolar / 3 AU
The force (F) = (4 * 3) / 3² = 4/3
b) 1 MEarth / 1 MSolar / 1 AU
The force (F) = (1 * 1) / 1² = 1
c) 1 MEarth / 2 MSolar / 2 AU
The force (F) = (1 * 2) / 2² = 1/2
Answer:
a) v = 2.4125 m / s , b) Em_{f} / Em₀ = 0.89
Explanation:
a) This is an inelastic crash problem, the system is made up of the four carriages, so the forces during the crash are internal and the moment is conserved
Initial
p₀ = m v₁ + 3 m v₂
Final
= (4 m) v
p₀ =p_{f}
m (v₁ + 3 v₂) = 4 m v
v = (v₁ +3 v₂) / 4
Let's calculate
v = (3.86 + 3 1.93) / 4
v = 2.4125 m / s
b) the initial mechanical energy is
Em₀ = K₁ + 3 K₂
Em₀ = ½ m v₁² + ½ 3m v₂²
The final mechanical energy
= K
Em_{f} = ½ 4 m v²
The fraction of energy lost is
Em_{f} / Em₀ = ½ 4m v² / ½ m (v₁² +3 v₂²)
Em_{f} / Em₀ = 4 v₂ / (v₁² + 3 v₂²)
Em_{f} / Em₀ = 4 2.4125² / (3.86² + 3 1.93²)
Em_{f} / em₀ = 23.28 / 26.07
Em_{f} / Em₀ = 0.89