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mash [69]
4 years ago
12

Which part of the atom forms chemical bonds?

Chemistry
2 answers:
Leokris [45]4 years ago
8 0
Out of the choices given, the part of the atom that forms chemical bonds are the outermost electrons. The correct answer is B. 
kompoz [17]4 years ago
7 0
B. The outermost electrons or the valence electrons of a given atom form chemical bonds that are covalent. These electrons are involved in chemical bonding.
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What causes objects to move or stay still?<br> Claim <br><br> Reasoning:<br><br> Evidence:
kari74 [83]

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For an object to move, there must be a force. A force is a push or pull that causes an object to move, change direction, change speed, or stop. Without a force, an object that is moving will continue to move and an object at rest will remain at rest.

Explanation:

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When two atoms are bonded together, the atom that is LEAST likely to attract electrons to itself is
Wewaii [24]

When two atoms are bonded together, the atom that is LEAST likely to attract electrons to itself is

the atom with the smallest electronegativity

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2 years ago
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An alkene with the molecular formula C8H16 undergoes ozonolysis to yield a mixture of (CH3)2C=O and (CH3)3CCHO. The alkene is:
aalyn [17]

Answer:

2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Explanation:

In ozonolysis (hydrolysis step involve a reducing agent such as Zn, Me_{2}S etc.), a pi bond is broken to form ketone/aldehyde.

Ketone is formed from di-substituted side of double bond and aldehyde is formed from mono-substituted side of double bond.

Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.

Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.

Here, 2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Reaction steps are shown below.

8 0
3 years ago
The activation energy of a reaction is 56.9 kj/mol and the frequency factor is 1.5×1011/s. Part a calculate the rate constant of
Vanyuwa [196]

We will use Arrehenius equation

lnK = lnA  -( Ea / RT)

R = gas constant = 8.314 J / mol K

T = temperature = 25 C = 298 K

A = frequency factor

ln A = ln (1.5×10 ^11) = 25.73

Ea = activation energy = 56.9 kj/mol = 56900 J / mol

lnK = 25.73 - (56900 / 8.314 X 298) = 2.76

Taking antilog

K = 15.8



5 0
4 years ago
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