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DanielleElmas [232]
3 years ago
15

A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 37.6 vibrations

in 27.9 s. Also, a given maximum travels 450 cm along the rope in 11.3 s. What is the wavelength? Answer in units of cm.
Physics
1 answer:
tangare [24]3 years ago
8 0

Answer:

\lambda = 25.79\ cm

Explanation:

given,

Wave vibrates = 37.6

time = 27.9 s

maximum distance travel = 450 cm

time = 11.3 s

wavelength = ?

frequency of wave

f=\dfrac{37.6}{27.9}

f = 1.35 Hz

Speed of wave

v = \dfrac{450}{11.3}

v = 39.82 cm/s

wavelength of wave

v = fλ

\lambda =\dfrac{v}{f}

\lambda =\dfrac{34.82}{1.35}

\lambda = 25.79\ cm

Hence, wavelength of the wave is equal to 25.79 cm.

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A satellite has a mass of 5832 kg and is in a circular orbit 4.13 × 105 m above the surface of a planet. The period of the orbit
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Answer:

W = 28226.88 N

Explanation:

Given,

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Height of the orbiting satellite from the surface, h = 4.13 x 10⁵ m

The time period of the orbit, T = 1.9 h

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The radius of the planet, R = 4.38 x 10⁶ m

The time period of the satellite is given by the formula

                             T = 2\pi \sqrt{\frac{(R+h)^{3} }{R^{2} g} }  second

Squaring the terms and solving it for 'g'

                             g = 4 π² \frac{(R+h)^{3} }{R^{2}T^{2}  }   m/s²

Substituting the values in the above equation

                   g = 4 π² \frac{(4.38X10^6+4.13X10^5)^{3} }{(4.38X10^6)^{2}X6840^{2}}  

                                    g = 4.84 m/s²      

Therefore, the weight

                                     w = m x g   newton

                                         = 5832 Kg x 4.84 m/s²

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Hence, the weight of the satellite at the surface, W = 28226.88 N                

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A 1500 kg car, initially traveling at 22.0 m/s, hits its brakes and skids to a stop. Determine the work done by friction.
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Answer:

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Explanation:

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Mathematically work done can be expressed as,

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<em>Substituting these values into equation 1</em>

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<em>W = 750 × 484</em>

<em>W = 363000 J</em>

<em>W = 363 kJ</em>

<em>Thus the work done by the car is 363 kJ</em>

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