PbCl2 and PbCl4
Empirical formula is when the molecular formula is reduced (each element) by the same number until you are unable to do so any further.
CH2O cannot be further reduced, but C3H6O3 can all be divided by 3 making it CH2O (same empirical formula)
3.5 moles of ammonia (NH₃) are produced
Explanation:
We have the following chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):
3 H₂ + N₂ → 2 NH₃
number of moles = mass / molecular weight
number of moles of N₂ = 48.97 / 28 = 1.75 moles
We see from the chemical reaction that 1 mole of N₂ will react with 3 moles of H₂, so 1.75 moles of nitrogen will react with 3 × 1.75 = 5.25 moles of H₂. We have 7.32 moles of H₂, a quantity more of what is needed, so the limiting reactant is N₂.
Knowing this we devise the following reasoning:
if 1 mole of N₂ produces 2 moles of NH₃
then 1.75 moles of N₂ produces X moles of NH₃
X = (1.75 × 2) / 1 = 3.5 moles of NH₃
Learn more about:
limiting reactant
brainly.com/question/7144022
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Answer:
On the periodic table, there are two numbers for every element: the atomic number and the atomic weight.
The numbers at the top of the square represents the number of protons present in the atom's nucleus of that element. This is called the atomic number.
For example, the atomic number for the element Krypton is 36. That means that there are 36 protons in the nucleus. If there were not 36 protons in the nucleus of that atom, that would create the atom of a completely different element. For example, if one proton was to be removed from the nucleus of the atom for the element of Krypton that atom will be an atom of the element bromine.
Explanation:
1) Dawn dish soap has a density of 1.06 g/mL. If the mass of a sample of the liquid is 1.00 g what is the volume?
Answer:
v = 0.94 mL
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Given data:
Density of soap = 1.06 g/mL.
Mass = 1 g
Volume = ?
Solution:
d = m/v
v = m/d
v = 1 g/1.06 g/mL
v = 0.94 mL
2) Maple syrup has a density of 1.37 g.mL. What is the mass of 1.0 L of the maple syrup?
Answer:
m = 1370 g
Given data:
Density of soap = 1.37 g/mL.
Mass = ?
Volume = 1.0 L ( 1000 mL)
Formula:
D=m/v
D= density
m=mass
V=volume
Solution:
d = m/v
m = d × v
m = 1.37 g/mL × 1000 mL
m = 1370 g
3) The density of gasoline is 0.754 g/mL. A drop of gasoline has a mass of 22 g what is the volume?
Answer:
v = 29.2 mL
Given data:
Density of soap = 0.754 g/mL.
Mass = 22 g
Volume = ?
Formula:
D=m/v
D= density
m=mass
V=volume
Solution:
d = m/v
v = m/d
v = 22 g/0.754 g/mL
v = 29.2 mL
