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amm1812
3 years ago
15

If you start with 0.05 M O3 and 0.01 M NO and the reaction reaches completion in 16 seconds, what is the initial rate of this re

action with respect to O3?
Chemistry
1 answer:
makvit [3.9K]3 years ago
6 0

Since we are basing the rate with respect to O3, therefore the rate would simply be the concentration divided by the total reaction time. That is:

rate of reaction = 0.05 M / 16 seconds

rate of reaction = 3.125 x 10^-3 M / second

or

<span>rate of reaction = 0.003125 M / second</span>

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Answer:

\large \boxed{\text{44.5 mL}}

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The measurements of 14.0 and 10.6 have one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.

The number to be dropped (3) is less than 5, so you drop it.

\text{The total volume of the three beakers is $\large \boxed{\textbf{44.5 mL}}$}

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