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amm1812
3 years ago
15

If you start with 0.05 M O3 and 0.01 M NO and the reaction reaches completion in 16 seconds, what is the initial rate of this re

action with respect to O3?
Chemistry
1 answer:
makvit [3.9K]3 years ago
6 0

Since we are basing the rate with respect to O3, therefore the rate would simply be the concentration divided by the total reaction time. That is:

rate of reaction = 0.05 M / 16 seconds

rate of reaction = 3.125 x 10^-3 M / second

or

<span>rate of reaction = 0.003125 M / second</span>

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anastassius [24]
Hello!
<span>
You'll need to react 7,5 moles of Sodium with sulfuric acid to produce 3.75 moles of sodium sulfate
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First of all, you need to balance the reaction. The balanced reaction is shown below (ensuring that the Law of Conservation of Mass is met on both sides):

2Na + H₂SO₄ → Na₂SO₄ + H₂

Now, all that you have to do is to use molar equivalences in this reaction applying the coefficients to calculate the moles of Sodium that you'll need:

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hi

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