Answer:
Here's what I find.
Explanation:
Many scientists contributed to our model of the atom.
Among those who received the Nobel Prize for their work are:
1906 — J.J. Thomson — discovery of the electron
1908 — Ernest Rutherford — nuclear model of the atom
1922 — Niels Bohr — planetary model of the atom
1922 — Albert Einstein — quantum mechanical model of the atom
1935 — James Chadwick — discovery of the neutron
Answer:
U are a fool
Explanation:
Because you didn't even asked a question
Answer:
Option C. Energy Profile D
Explanation:
Data obtained from the question include:
Enthalpy change ΔH = 89.4 KJ/mol.
Enthalpy change (ΔH) is simply defined as the difference between the heat of product (Hp) and the heat of reactant (Hr). Mathematically, it is expressed as:
Enthalpy change (ΔH) = Heat of product (Hp) – Heat of reactant (Hr)
ΔH = Hp – Hr
Note: If the enthalpy change (ΔH) is positive, it means that the product has a higher heat content than the reactant.
If the enthalpy change (ΔH) is negative, it means that the reactant has a higher heat content than the product.
Now, considering the question given, the enthalpy change (ΔH) is 89.4 KJ/mol and it is a positive number indicating that the heat content of the product is higher than the heat content of the reactant.
Therefore, Energy Profile D satisfy the enthalpy change (ΔH) for the formation of CS2 as it indicates that the heat content of product is higher than the heat content of the reactant.
1) Data:
T₁ = <span>
21°C
</span>
<span>T₂ = 51°C.
</span>
<span>V₁ = V₂ = 15.6 L
</span>
<span>P₁ = 249 kPa.
</span>
<span>Pb = 269 kPa.
</span>
<span>Questions:
</span>
• n = ?
• P₂ = ?
• Will the tires burst at the peak temperature? Explain.
• To what pressure should the tire pressure be reduced before starting
the ride to avoid bursting of the tires in the desert heat? (Assume no
significant change in tire volume.)
Pi = ?
2) Formula:
PV = nRT
P₁ / T₁ = P₂ / T₂
3) Solution
i) n
P₁V₁ = nRT ⇒ n = P₁V₁ / [RT₁]
n = 249 kPa × 15.6 liter / [8.314 (liter-kPa / mol-K) × (21 + 273.15K) ] =
n = 1.588 mol
ii) P₂
P₂ = P₁ T₂ / T₁ = 249 kPa (50 + 273.15 K) / (21 + 273.15K) = 273.5 kPa
iii) Tires will burst, since P₂ > Pb
iv) Pi
Pi / T₁ = Pb / T₂
Pi = Pb T₁ / T₂ = 269 kPa (21 + 273.15K) / (50 + 273.15K) = 244.9 kPa
The pressure shoul to be reduced to less than 244.9 kPa before starting to avoid the <span> bursting of the tires in the desert heat.</span>
