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Aleksandr-060686 [28]
3 years ago
9

Si tomas 100ml de una solución de Nacl 4m y se disuelve en 200ml utilizando el mismo solvente ¿cuál será la nueva concentración?

Chemistry
1 answer:
g100num [7]3 years ago
3 0

Respuesta:

2 m

Explicación:

Paso 1: Información provista

  • Volumen inicial (V₁): 100 mL
  • Concentración inicial (C₁): 4 m
  • Volumen final (V₂): 200 mL
  • Concentración final (C₂): ?

Paso 2: Calcular la concentración de la solución final

Queremos perparar una concentración diluida a partir de una concentrada. Podemos calcular la concentración de la solución diluida usando la regla de dilución.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 4 m × 100 mL / 200 mL = 2 m

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Calculate the molarity of 13.1 g of NaCl in 727 mL of solution
valentina_108 [34]

Answer:

The molarity of the solution is 0,31 M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

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x=0,308 mol NaCl---> <em>The solution is 0,31 molar (0,31 M)</em>

5 0
3 years ago
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Sonja [21]

Answer:

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5 0
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Ne4ueva [31]

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Explanation:

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Ua/Ub= √(Mb/Ma)

Where Ua/Ub is the ratio of velocity of hydrogen to carbon dioxide and Ma is the molecular mass of hydrogen gas= 2

Mb is the molecular mass of CO2 = 44

Therefore

Ua/Ub= √(44/2)

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Therefore the ratio of velocity of hydrogen gas to carbon dioxide = 1:4.69

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8 0
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Explanation:

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8 0
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