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3 years ago

Si tomas 100ml de una solución de Nacl 4m y se disuelve en 200ml utilizando el mismo solvente ¿cuál será la nueva concentración?

Chemistry

1 answer:

g100num [7]3 years ago

3 0

Respuesta:

2 m

Explicación:

Paso 1: Información provista

Volumen inicial (V₁): 100 mL

Concentración inicial (C₁): 4 m

Volumen final (V₂): 200 mL

Concentración final (C₂): ?

Paso 2: Calcular la concentración de la solución final

Queremos perparar una concentración diluida a partir de una concentrada. Podemos calcular la concentración de la solución diluida usando la regla de dilución.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 4 m × 100 mL / 200 mL = 2 m

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1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride ? atoms of boron.

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Answer:

1. How many ATOMS of boron are present in 2.20 moles of boron trifluoride? atoms of boron.

2. How many MOLES of fluorine are present in of boron trifluoride? moles of fluorine.

Explanation:

The molecular formula of boron trifluoride is $BF_3$ .

So, one mole of boron trifluoride has one mole of boron atoms.

1. The number of boron atoms in 2.20 moles of boron trifluoride is 2.20 moles.

The number of atoms in 2.20 moles of boron is:

One mole of boron has ---- $6.023x10^2^3$ atoms.

Then, 2.20 moles of boron has

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2. Calculate the number of moles of BF3 in 5.35*1022 molecules.

$(5.35x10^2^2 molecules/6.023x10^2^3)x 1mol\\=0.0888mol$

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Hence, 0.0888moles of BF3 has 3x0.0888mol of fluorine atoms.

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2 years ago

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Answer:

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Mass of water = 50g

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Initial temperature = ?

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To solve this problem, we use the expression below:

H = m c Ф

H is the energy absorbed

m is the mass

c is the specific heat capacity

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