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aivan3 [116]
3 years ago
8

Need help with this please

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0
The second graph is correct.    Because the first equation is <= -x-1, it must fall under that line: only the second and fourth graphs do so.  The second equation, >=2x+4, means it must fall above that line: only the second and third graphs do so.  
V125BC [204]3 years ago
5 0
B (the second one) is the correct answer. 

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Write the slope-intercept form of the equation for the line given the slope and y-intercept (equation: y=mx+b) Slope = 5, y-inte
Rufina [12.5K]

Answer:

y=5x+2

Step-by-step explanation:

Slope formula:

y=mx+b

- m stands for slope

- b stands for y intercept.

Plug the information in:

y=5x+2

3 0
3 years ago
find two positive real numbers such that they sum to 108 and the product of the first times the square of the second is a maximu
topjm [15]

The two positive numbers are 36 and 72 which gives a sum equal to 108 and the product of 36 and the square of 72 is a maximum.

Any integer greater than zero is considered a positive number. A positive number can either be written as a number or with the "+" symbol in front of it.

Let us consider the two positive real numbers as x and y. Then, their sum is written as,

x+y=108

Then, y=108-x

And the product is written as,

P=xy²

Substitute value of y in the above equation, we get,

\begin{aligned}P&=x(108-x)^2\\&=x(11664-216x+x^2)\\&=11664x-216x^2+x^3\\&=x^3-216x^2+11664x\end{aligned}

Now, differentiate P with respect to x, and we get,

\begin{aligned}\frac{dP}{dx}&=3x^2-432x+11664\\&=x^2-144x+3888\end{aligned}

Solving the above equation to zero, we get,

\begin{aligned}x^2-144x+3888&=0\\x^2-36x-108x+3888&=0\\x(x-36)-108(x-36)&=0\\(x-108)(x-36)&=0\\x&=\text{108 or 36}\end{aligned}

Substitute values of x in y=108-x, to get values of y.

If we substitute x=108, we get the y value as zero which doesn't give the required solution.

But, if we substitute x=36, we get,

\begin{aligned}y&=108-36\\y&=72\end{aligned}

Thus, the two positive numbers are 36 and 72.

To know more about positive numbers:

brainly.com/question/1635103

#SPJ4

4 0
1 year ago
2. Find the perimeter of a rectangle of<br> Length 13m with an area of 65m
I am Lyosha [343]

Answer:

Perimeter = 36m

Step-by-step explanation:

Area = l x w

65m = 13m x w

5m = w

Perimeter = 2(l + w)

Perimeter = 2(13m + 5m)

Perimeter = 36m

3 0
3 years ago
Read 2 more answers
can anyone help me with this? i know how to solve it I just dont know the reasons and statement definitions
MAVERICK [17]
If you do a check (plug in your answer to y) that would be your reason
8 0
3 years ago
Help me, its trigonometry college
prohojiy [21]

4) (a) For these problems, you should take time to familiarize yourself with common fractions that appear on the unit circle.  \frac{\sqrt{3}} {3} does not appear in the unit circle unless you take the quotient 1/2 divided by sqrt(3)/2 which gives you 1/sqrt(3) which is the same as sqrt(3)/3.  So our numerator is 1/2 and our denominator is sqrt(3)/2.

And remember tangent is just sin/cos.  So what degree has sinx as 1/2 and and cosx as sqrt(3)/2?  Well, 30 degrees does, but 30 degrees is not within the range we are given.  That means they are looking for a sinx that gives us -1/2 and a cosx that gives us -sqrt(3)/2 and that is 210 degrees.

And 210 degrees in radians is 7pi/6.

I hoped that made sense.

(b) This is a lot easier. What angle gives us a cos x of -sqrt(3)/2?  According to the unit circle, 150 degrees and 210 degrees does.  They usually want these in radians, so the answer is 5pi/6 and 7pi/6, respectively.

5) What quadrant is radian measure 5 in?

Well 2pi or roughly 6.28 is a full circle. And 5 is slightly less than 6.28, so it is probably in quadrant IV.

But to be sure let's change 5 radian to degrees:

5 * 180/pi = 900/pi = 286.48 degrees

286.48 degrees is definitely in Q4, so we are correct.




7 0
3 years ago
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