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3 years ago

Need help with this please

Mathematics

2 answers:

Galina-37 [17]3 years ago

8 0

The second graph is correct. Because the first equation is <= -x-1, it must fall under that line: only the second and fourth graphs do so. The second equation, >=2x+4, means it must fall above that line: only the second and third graphs do so.

V125BC [204]3 years ago

5 0

B (the second one) is the correct answer.

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How many solutions are there to the equation below?

elena55 [62]

Answer:

A) 0 (no solutions)

Step-by-step explanation:

Solve the equation:

3x - 10(x+2) = 13 - 7x

3x - 10x -20 = 13 - 7x

-7x - 20 = 13 - 7x

-20 = 13

Since both sides are clearly not equal to each other, no solution can satisfy both sides to be equal to each other. So A is correct.

5 0

3 years ago

Read 2 more answers

A half of a class and a half of a student got A on a test. If yet another student got an A, then two-thirds of the class would h

Cerrena [4.2K]

Answer:

Step-by-step explanation:

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3 years ago

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago

Two sevenths of a number subtracted from two fifths of that same number is 8. find the number

Allisa [31]

2/7x - 2/5x = 8
multiply both sides by 35
= 10x - 14x = 280
combine 10x and 14x
= -4x = 280
divide both sides by -4
x= -70

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3 years ago

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lina2011 [118]

I don’t understand. lol

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3 years ago