Question

How many moles of neon gas are there 25.0 L of gas or 5.0°C with a pressure of 89.9 KPa?

Answer 1

• Volume=25L
• Temperature=5°C
• Pressure=89.9kPa

Now

$\\ \rm\rightarrowtail PV=nRT$

$\\ \rm\rightarrowtail n=\dfrac{PV}{RT}$

$\\ \rm\rightarrowtail n=\dfrac{89.9(25)}{5R}$

$\\ \rm\rightarrowtail n=89.9(5)/R$

$\\ \rm\rightarrowtail n=449.5/R mol$