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Genrish500 [490]
3 years ago
8

How can i determin the size of my car

Chemistry
1 answer:
nadya68 [22]3 years ago
4 0

Answer:

ehat the guy above said

Explanation:

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By definition 12 grams of carbon-12 must contain how many atoms?
krek1111 [17]
It is defined as the amount of a substance that contains as many particles as there are atoms in 12 grams of pure carbon-12. So, 1 molecule contains 6.022×10^23 elementary entities of the substance.

Hope that helps
5 0
3 years ago
WORTH 100 POINTS
hjlf

Answer:

When 0.250 moles of a gas is placed in a container at 25 °C, it exerts a pressure of 700 mm Hg.

Explanation:

5 0
3 years ago
How many atoms are in 8.28 moles of aluminum?
Lilit [14]

Answer:

49.86 × 10²³  atoms of Al

Explanation:

Given data:

Number of moles of Al = 8.28 mol

Number of atoms = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 8.28 moles of Al:

1 mole = 6.022 × 10²³  atoms of Al

8.28 mol×6.022 × 10²³  atoms / 1mol

49.86 × 10²³  atoms of Al

4 0
3 years ago
Determine the mass, in grams, of 0.350 moles of s (1 mol of s has a mass of 32.07 g).
hram777 [196]

Answer:

11.22 gm

Explanation:

32.07 gm / mole * .350 mole = 11.22 gm

4 0
2 years ago
Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in
Pani-rosa [81]

Answer:

666,480 Joules or 669.48 kJ

Explanation:

We are given;

  • Volume of water as 2.0L or 2000 ml

but, density of water is 1 g/ml

  • Therefore, mass of water is 2000 g
  • Initial temperature as 20 °C
  • Final temperature as 99.7° C

Required to determine the heat change

We know that ;

Heat change = Mass × Temperature change × specific heat

In this case;

Specific heat of water is 4.2 J/g°C

Temperature change is 79.7 °C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

                      = 669,480 Joules 0r 669.48 kJ

Thus, the heat change involved is 666,480 Joules or 669.48 kJ

5 0
3 years ago
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