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Karolina [17]
3 years ago
10

What is the fault-current circuit breaker? Describe its function.

Physics
2 answers:
Nimfa-mama [501]3 years ago
4 0

Answer:

A circuit breaker is a switching mechanism that interrupts the current that is irregular or fault. It is a mechanical system that interferes with high magnitude (fault) current flow and also performs a transfer operation. Hope this helps :)

Explanation:

AleksandrR [38]3 years ago
4 0

Answer:

A circuit breaker is an electrical switch designed to protect an electrical circuit from damage caused by an overcurrent or short circuit.

Explanation:

Its basic function is to interrupt current flow after protective relays detect a fault.

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A computer is purchased for $2816 and depreciates at a constant rate to $0 in 8 years. Find a formula for the value, V , of the
marusya05 [52]

Answer:

  • The formula its f(t) \ = \ - \ 352 \ \frac{\$ }{years} \ t \ + \ \$ \ 2816
  • After 5 years, the computer value its $ 1056

Explanation:

<h3>Obtaining the formula</h3>

We wish to find a formula that

  • Starts at 2816. f(0 \ years) \ = \ \$ \ 2816
  • Reach 0 at 8 years. f( 8 \ years) \ = \ \$ \ 0
  • Depreciates at a constant rate. m

We can cover all this requisites with a straight-line equation. (an straigh-line its the only curve that has a constant rate of change) :

f(t) \ = \ m\ t \ + \ b,

where m its the slope of the line and b give the place where the line intercepts the <em>y</em> axis.

So, we can use this formula with the data from our problem. For the first condition:

f ( 0 \ years ) = m \ (0 \ years) + b = \$ \ 2816

b = \$ \ 2816

So, b = $ 2816.

Now, for the second condition:

f ( 8 \ years ) = m \ (8 \ years) + \$ \ 2816 = \$ \ 0

m \ (8 \ years) = \ - \$ \ 2816

m = \frac{\ - \$ \ 2816}{8 \ years}

m = \frac{\ - \$ \ 2816}{8 \ years}

m = \ - \ 352 \frac{\$ }{years}

So, our formula, finally, its:

f(t) \ = \ - \ 352 \ \frac{\$ }{years} \ t \ + \ \$ \ 2816

<h3>After 5 years</h3>

Now, we just use <em>t = 5 years</em> in our formula

f(5 \ years) \ = \ - \ 352 \ \frac{\$ }{years} \ 5 \ years \ + \ \$ \ 2816

f(5 \ years) \ = \ - \$ \ 1760 + \ \$ \ 2816

f(5 \ years) \ = $ \ 1056

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4 years ago
What is one way homeostasis benefits living organisms?
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Answer:

it maintains balance, it keeps body temperatures , heart rate and all other bodily functions regulated to keep the organism stable when the environment is not.

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3 years ago
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How many squares are in 2×2 grid?
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Four squares are in a 2×2 grid.
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4 years ago
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The force acting between two charged particles a and b is 5.2 x 10^-5 newtons. Charges a and b are 2.4 x 10^-2 apart. If the cha
Aneli [31]
4.62x10^-11
hope this helped!
5 0
4 years ago
A 500g air-track glider attached to a spring with spring constant 10 N/m is sitting at rest on a frictionless air track. A 250 g
d1i1m1o1n [39]

To solve this problem it is necessary to apply the conservation equations of the moment for an inelastic impact or collision. In turn, it is necessary to apply the equations related to the conservation of potential energy and kinetic energy.

Mathematically this definition can be expressed as

m_1v_1+m_2v_2=(m_1+m_2)v_f

Where,

v_{1,2} = Initial velocity of each object

m_{1,2} =Mass of each object

v_f =Final velocity

Our values are given as

m_1 = 0.25kg\\m_2 = 0.5kg\\v_1 = 1.2m/s\\v_2 = 0m/s

Replacing we can find the value of the final velocity, that is

0.750v_f = 0.25*1.20+0.5*0

v_f = 0.4m/s

From the definition of the equations of simple harmonic motion the potential energy of compression and equilibrium must be subject to

KE_{compressed}+PE_{compressed} =KE_{equilibrium} +PE_{equilibrium}

Since there is no kinetic energy due to the zero speed in compression, nor potential energy at the time of equilibrium at the end, we will have to

0+\frac{1}{2}KA^2 = \frac{1}{2}(m_1+m_2)v_f^2+0

Re-arrange to find A

A = \sqrt{\frac{m_1+m_2}{k}v_f}

A = \sqrt{\frac{0.25+0.5}{10}(0.4)}

A = 0.11m

Finally, the period can be calculated through the relationship between the spring constant and the total mass, that is,

T = 2\pi \sqrt{\frac{m_1+m_2}{k}}

T = 2\pi \sqrt{\frac{0.5+0.25}{10}}

T = 1.7s

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