Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;

then;

or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
Answer:
X=3,1/4
Step-by-step explanation:
4x²-(12+1)x+3=0
or,4x²-12x-x+3=0
or,4x(x-3)-1(x-3)=0
or,(4x-1)(x-3)=0
Either,4x-1=0➡️ 4x=1
X=1/4
OR,x-3=0➡️ X=3
Answer:
Step-by-step explanation:

given: 
$\therefore Ac=\frac{(2)2}{2}=2$