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r-ruslan [8.4K]
3 years ago
13

What is the phrase of warm air cold air

Chemistry
1 answer:
Dominik [7]3 years ago
3 0
I'm pretty sure the answer is 'fronts'
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What is sodium diacetate?
Lostsunrise [7]
Sodium Diacetate is a compound with the formula of NaH2. it is a salt of acetic acid. it is a colorless liquid that is used in seasonings and as an antimicrobial agent.
7 0
3 years ago
Read 2 more answers
i’m currently focusing on my algebra so i need a little help on a science study guide, i can’t post multiple pictures on the pag
riadik2000 [5.3K]

which question do you need help on

8 0
3 years ago
What part of the atom determines if it will combine or break apart from other substances?
anzhelika [568]

<em>Answer:</em>

  • The atom consist of three parts, proton, neutron and electrons. The electrons determine that i will combine or beak from other substances.

<em>Explanation:</em>

The atom consist of three parts which are following

  • proton
  • neutron
  • electron

The proton and neutron form nucleus of an atom. It is present at center of an atom. They have positive charges, while electrons remained outside the nucleus in particular energy levels or shell around the nucleus.

During combination or breaking of substances ,only arrangements of electrons take place. The valence shell electrons decide whether they have to combine or not, while nucleus remained unchanged during any reactions.

3 0
3 years ago
Ch4+202==&gt;c02+302 what type of chemical reaction
n200080 [17]

Answer:

First of all, the equation is typed wrong so it can easily be misinterpreted

Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)

CH4 + 2O2 -----> CO2 + 2H2O

And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.

4 0
2 years ago
What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)
rewona [7]

Answer:

Ka = 4.04 \times 10^{-11}

Explanation:

Initial concentration of weak acid = 4.5 \times 10^{-4}\ M

pH = 6.87

pH = -log[H^+]

[H^+]=10^{-pH}

[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M

HA dissociated as:

HA \leftrightharpoons H^+ + A^{-}

(0.00045 - x)    x     x

[HA] at equilibrium = (0.00045 - x) M

x = 1.35 \times 10^{-7}\ M

Ka = \frac{[H^+][A^{-}]}{[HA]}

Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}

0.000000135 <<< 0.00045

Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}

5 0
3 years ago
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