Answer:
A
Explanation:
Iron and gadlinium are both very easily made into magnetic substances. Cobalt is also capable of being magnetized. Aluminum, put in an alloy, can make a magnetic substance, but
Aluminum by itself is not able to be magnetized.
Answer:
6
Explanation:
Number of lines emanate from + 5 micro coulomb is 15 .
They terminates at negative charges that means at - 3 micro coulomb and - 2 micro Coulomb.
the electric field lines terminates at - 3 micro Coulomb and - 2 micro Coulomb is in the ratio of 3 : 2.
So the lines terminating at - 3 micro coulomb
= 
So the lines terminating at - 2 micro coulomb
= 
So, the number of filed lines terminates at - 2 micro Coulomb are 6.
There is no definite end to earths atmosphere, but technically the border between the outer space and earth gets thinner as you move up from the earths surface. The Karman line is the closest definition there is which describes the end of the earth's atmosphere, it is 100 km above earth's sea level at approximately 1.56 % of total earth's radius. This describes the boundary between the outer space and the atmosphere.
Answer:
The equation which describes conservation of charge is 
Explanation:
The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.
let the sum of initial charges = 
let the sum of the final charges = 

Therefore, the equation which describes conservation of charge is 
Answer:
pressure in cylinder A must be one third of pressure in cylinder B
Explanation:
We are told that the temperature and quantity of the gases in the 2 cylinders are same.
Thus, number of moles and temperature will be the same for both cylinders.
To this effect we will use the formula for ideal gas equation which is;
PV = nRT
Where;
P is prrssure
V is volume
n is number of moles
T is temperature
R is gas constant
We are told that Cylinder A has three times the volume of cylinder .
Thus;
V_a = 3V_b
For cylinder A;
Pressure = P_a
Volume = 3V_b
Number of moles = n
Thus;
P_a × 3V_b = nRT
For cylinder B;
Pressure = P_b
Volume = V_b
Number of moles = n
Thus,
P_b × V_b = nRT
Combining the equations for both cylinders, we have;
P_a × 3V_b = P_b × V_b
V_b will cancel out to give;
3P_a = P_b
Divide both sides by 3 to get;
P_a = ⅓P_b
Thus, pressure in cylinder A must be one third of pressure in cylinder B