How many atoms of each element are in the chemical formula NH4NO3?
2 answers:
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The flow rate is 17gtts/min.
<h3>What is the drug infusion rate?</h3>- The rate of infusion (or dosing rate) in pharmacokinetics refers to the ideal rate at which a drug should be supplied to achieve a steady state of a fixed dose that has been shown to be therapeutically effective. This rate is not only the rate at which a drug is administered.
- The infusion volume is divided into drops, which is known as a drip-rate. The Drip Rate formula is as follows: Volume (mL) times time (h) equals drip-rate. A patient must get 1,000 mL of intravenous fluids over the course of eight hours.
- Infusion rates of 3–4 mg/kg per minute are advised by manufacturers to reduce rate-related adverse effects. Usually, the infusion lasts for several hours. Although not advised, rates exceeding 5 mg/kg per hour may be tolerated by some patients.
- If no negative reactions occur, the rate may be increased in accordance with the table every 30 minutes up to a maximum rate of 3 ml/kg/hour (not to exceed 150 ml/hour).
To find the flow rate is 17gtts/min:
Therefore, The flow rate is 17gtts/min.
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Answer:
The charge on the capacitor had increased
Explanation:
The expression for the capacitance of an air-filled parallel-plate capacitor is as follows as;
Here, C is the capacitance, is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.
When a slab of dielectric material is placed between the plates of the capacitor then the expression for the capacitance is as follows;
Here, K is the dielectric constant.
In the given problem, a slab is inserted between the plates of the capacitor then the capacitance of the capacitor will increase in this case. Therefore, the option (a) is true.
The expression for the charge stored in the capacitor is as;
Q= CV
Here, Q is the charge and V is the potential.
The charge will also increase in this case as the charge stored in the capacitor is directly proportional to the capacitance. Therefore, the option (d) is not true.
The expression for the energy stored in the capacitor is as follows;
The voltage is constant in the given problem but the capacitance increases then the energy stored in the capacitor will increase. Therefore, the option (b) is not true.
The voltage across the capacitor will remain same as the capacitor is still connected to the battery. Therefore, the option (c) is not true.
Therefore, only option (a) is true.