Answer:
5.450 mol Si₃N₄
Explanation:
Step 1: Write the balanced equation
3 Si + 2 N₂ ⇒ Si₃N₄
Step 2: Establish the theoretical molar ratio between the reactants
The theoretical molar ratio of Si to N₂ is 3:2 = 1.5:1.
Step 3: Establish the experimental molar ratio between the reactants
The experimental molar ratio of Si to N₂ is 16.35:11.26 = 1.45:1. Comparing both molar ratios, we can see that Si is the limiting reactant.
Step 4: Calculate the moles of Si₃N₄ produced from 16.35 moles of Si
The molar ratio of Si to Si₃N₄ is 3:1.
16.35 mol Si × 1 mol Si₃N₄/3 mol Si = 5.450 mol Si₃N₄
8.24g
Explanation:
Given parameters;
Mass of NH₃ = 10g
Unknown:
Mass of N₂ = ?
Solution:
Reaction equation:
N₂ + 3H₂ → 2NH₃
Step 1: Convert 10.0 g of NH₃ into moles of NH₃
number of moles = 
molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles =
= 0.59mole
Step 2: Convert the moles of NH₃ calculated in Step 1 into moles of N₂
1 mole of N₂ produced 2 mole of NH₃
0.59 moles of ammonia would be formed by
mole = 0.29mole of N₂
Step 3: Convert the moles of N₂ calculated in Step 2 into grams of N₂.
Mass of N₂ = number of moles x molar mass
Molar mass of N₂ = 14 x 2 = 28g/mol
Mass of N₂ = 0.29 x 28 = 8.24g
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Number of moles brainly.com/question/1841136
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