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Luda [366]
3 years ago
10

what is the resistance of a light bulb if a potential difference of 120 v will produce a current of 0.5 a in the bulb? 0.0042 0.

5 60 240
Physics
2 answers:
Bas_tet [7]3 years ago
8 0

Answer:

240 ohms or D

Explanation:

svlad2 [7]3 years ago
3 0
R = V/I

R = 120 V/ 0.5 A

R = 240 ohms
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Сс<br> Explain the effect of Earth's gravity on objects on the<br> surface of Earth.
dem82 [27]

Answer:

The effect of gravity on object makes objects stable and not floating in the air . It also makes any object thrown up to return back

6 0
3 years ago
A projectile of mass m is fired horizontally with an initial speed of v0​ from a height of h above a flat, desert surface. Negle
Grace [21]

Complete question is;

A projectile of mass m is fired horizontally with an initial speed of v0 from a height of h above a flat, desert surface. Neglecting air friction, at the instant before the projectile hits the ground, find the following in terms of m, v0, h and g:

(a) the work done by the force of gravity on the projectile,

(b) the change in kinetic energy of the projectile since it was fired, and

(c) the final kinetic energy of the projectile.

(d) Are any of the answers changed if the initial angle is changed?

Answer:

A) W = mgh

B) ΔKE = mgh

C) K2 = mgh + ½mv_o²

D) No they wouldn't change

Explanation:

We are expressing in terms of m, v0​, h, and g. They are;

m is mass

v0 is initial velocity

h is height of projectile fired

g is acceleration due to gravity

A) Now, the formula for workdone by force of gravity on projectile is;

W = F × h

Now, Force(F) can be expressed as mg since it is force of gravity.

Thus; W = mgh

Now, there is no mention of any angles of being fired because we are just told it was fired horizontally.

Therefore, even if the angle is changed, workdone will not change because the equation doesn't depend on the angle.

B) Change in kinetic energy is simply;

ΔKE = K2 - K1

Where K2 is final kinetic energy and K1 is initial kinetic energy.

However, from conservation of energy, we now that change in kinetic energy = change in potential energy.

Thus;

ΔKE = ΔPE

ΔPE = U2 - U1

U2 is final potential energy = mgh

U1 is initial potential energy = mg(0) = 0. 0 was used as h because at initial point no height had been covered.

Thus;

ΔKE = ΔPE = mgh

Again like a above, the change in kinetic energy will not change because the equation doesn't depend on the angle.

C) As seen in B above,

ΔKE = ΔPE

Thus;

½mv² - ½mv_o² = mgh

Where final kinetic energy, K2 = ½mv²

And initial kinetic energy = ½mv_o²

Thus;

K2 = mgh + ½mv_o²

Similar to a and B above, this will not change even if initial angle is changed

D) All of the answers wouldn't change because their equations don't depend on the angle.

5 0
3 years ago
A 0.210-kg metal rod carrying a current of 11.0 A glides on two horizontal rails 0.490 m apart. If the coefficient of kinetic fr
sergij07 [2.7K]

Answer:

The  magnetic field is  B = 0.0764 \ T

Explanation:

From the question we are told that  

    The mass of the metal is  m  =  0.210 \ kg

     The current is  I  =  11.0 \ A

      The distance between the rail(length of the rod ) is  d  =  0.490 \ m

      The coefficient of kinetic friction is  \mu_k  =  0.200

Generally the magnetic force is mathematically represented as

      F_b  =  B *  I  *  d

Given that the rod is moving at a constant velocity, it

=>    F_b  =  F_k

Where F_k is the kinetic frictional force which is mathematically represented as

       F_k  =  \mu_k  *  m *  g

So

    B *  I  *  d =  \mu_k  * m * g

=>   B =  \frac{\mu_k  * m * g}{I  *  d }

substituting values

=>   B =  \frac{0.200  * 0.210  * 9.8 }{ 11  *  0.490 }

=>   B = 0.0764 \ T

3 0
2 years ago
An air filter can remove dust particles from air but will reach capacity (saturation) at 50.0 mg. Of air containing 225 µg dust
zubka84 [21]

Answer:

Time to Reach Saturation = 0.0146 day

Explanation:

In order to solve this problem, we first need to calculate the dust filtered by the filter per cubic meter of air:

Filtered Dust per m³ = Dust Particles Entering per m³ - Dust Particles Leaving per m³

Filtered Dust per m³ = 225 μg/m³ - 15 μg/m³

Filtered Dust per m³ = 210 μg/m³ = 210 x 10⁻³ mg/m³

Now, we find volume flow rate of air through filter:

Volume Flow Rate of Air = (400 ft³/min)(0.3048 m/1 ft)³

Volume Flow Rate of Air = 11.33 m³/min

Now, we calculate rate of dust filtered:

Rate of Dust Filtered = (Filtered Dust per m³)(Volume Flow Rate of Dust)

Rate of Dust Filtered = (210 x 10⁻³ mg/m³)(11.33 m³/min)

Rate of Dust Filtered = 2.38 mg/min

Now, for the time required to reach saturation:

Time to Reach Saturation = (Saturation Capacity)/(Rate of Dust Filtered)

Time to Reach Saturation = (50 mg)/(2.38 mg/min)

Time to Reach Saturation = (21.02 min)(1 day/24 h)(1 h/60 min)

<u>Time to Reach Saturation = 0.0146 day</u>

3 0
3 years ago
A negative acceleration means that the speed of the object decreases. What makes this sentene incorrect?
Sophie [7]
It's not the speed , it's the rate of change of the speed decreases 
4 0
3 years ago
Read 2 more answers
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