2 years ago

What material of mass 39g,has a volume of 5cm^3

Physics

1 answer:

insens350 [35]2 years ago

4 0

The material of density 7.8 g/cm³

You might be interested in

Calculate the amount of energy produced in joules by 100- watt light bulb lit for 2.5 hours.

9966 [12]

100/2.5 is 40.
40 is the energy that is being produced

4 0

3 years ago

Show that 1.0 m/s = 3.6 km/h . Hint: Show the explicit steps involved in converting 1.0 m/s = 3.6 km/h.

sergiy2304 [10]

Just multiply the "1.0 m/s" by ' 1 ' a few times. (Remember that a fraction with the same quantity on top and bottom is equal to ' 1 ' .)

(1.0 m/sec) · (1 km/1000 m) · (60 sec/min) · (60 min/hr) =

(1.0 · 60 · 60 / 1,000) (m · km · sec · min / sec · m · min · hr) =

(3,600 / 1,000) (km / hr) =

3.6 km/hr .

5 0

3 years ago

Hi to answer this question you need to be in 5th grade or older

777dan777 [17]

The answer is A.They push one another apart

5 0

3 years ago

The belt of one ramp moves at a constant speed such that a person who stands still on it leaves the ramp 64 s after getting on.

Bad White [126]

Answer:

0.74 m/s

Explanation:

given,

time taken by the ramp to cover cliff , t = 64 s

acceleration = 0.37 m/s²

distance traveled by the belt

$x = v_{belt}t_{belt}$

Clifford is moving with constant acceleration

$x = v_ot + \dfrac{1}{2}at^2$ ...(1)

initial velocity is equal to zero

$x =\dfrac{1}{2}at^2$ ........(2)

equating equation (1) and (2)

$v_{belt}t_{belt}=\dfrac{1}{2}at^2$

$v_{belt}t_{belt}=\dfrac{1}{2}a(\dfrac{1}{4}\times t_{belt})^2$

$v_{belt}=\dfrac{1}{32}a t_{belt}$

$v_{belt}=\dfrac{1}{32}\times 0.37 \times 64$

$v_{belt}= 0.74\ m/s$

Speed of the belt is equal to 0.74 m/s

3 0

3 years ago

Which scale has 100 divisions from when the temperature when water freezes to the temperature when water boils

Westkost [7]

The Celsius scale ( $^{\circ} C$ ).

In the Celsius temperature scale, the temperature at which water freezes is set conventionally at $0^{\circ}C$ , while the temperature at which the water boils is set at $100^{\circ}C$ . The Celsius degree is then defined as the unit corresponding to 1/100 of this time interval, between the temperature of freezing and boiling of the water.

8 0

2 years ago