Answer:
greater
Explanation:
Let the initial velocity is u .
Acceleration due to gravity on earth, ge = g
Acceleration due to gravity on moon, gm = g / 6
Let the maximum height reached on earth is h and the maximum height reached on the moon is h'.
Use third equation of motion
At maximum height, the final velocity = 0.
For earth
0 = u^2 - 2 gh
h = u^2 / 2g ..... (1)
For moon
0 = u^2 - 2 g/6 x h'
h' = 6u^2 / 2g = 6 h (From (1)
So, the maximum height reached at moon is 6 times the maximum height reached at earth.
Answer:
m=image distance÷object distance
Reference point is the answere
Answer:
84%
Explanation:
g = Acceleration due to gravity = 9.81 m/s²
x = 10 m
t = Time taken
= 3.5 m/s (assumed, as it is not given)
We have the equation
From continuity equation we have
Fraction is given by
The fraction is 84%
Rise over run at 1 second
It’s the same slope from 0 to 2 seconds
10/2=5mps
As a note all time points between 0and 2 will have this instantaneous velocity
Instantaneous velocity at time 2 is 0