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natulia [17]
4 years ago
7

In the parallelogram shown, AE = t + 2, CE = 3t − 14, and DE = 2t + 8.

Physics
2 answers:
solniwko [45]4 years ago
7 0
The answer would be 48
S_A_V [24]4 years ago
4 0
The answer is C 48 units
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The name of the SI unit for force is the watt<br> \
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Explanation:

The name of the SI unit for force is NEWTON .

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A sound system is being set up in a gazebo in a park. It needs to produce music so that everyone can hear it. How much power wou
Agata [3.3K]

Answer:

Power of the speakers = 1.57 \times 10^{-6} W

Explanation:

There are speakers setup in a park and we have to find the power it would require to have intensity of sound to be 10^{-8} W/m^2 at a distance of 5 meter.

In one dimension the intensity is constant as the wave travels. In two or three dimensions, however, the intensity decreases as you get further from the source.

Intensity is inversely proportional to the square of the distance from the point of sound production.

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area = 157 m^{2}

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Power = intensity \times area

Power = 10^{-8} \times 157Power = 1.57 [tex]\times 10^{-6} W

7 0
3 years ago
Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water st
AlekseyPX

Explanation:

Initial speed of the incident water stream, u = 16 m/s

Final speed of the exiting water stream, v = -16 m/s

The mass of water per second that strikes the blade is 48.0 kg/s.

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F=48\times (-16-16)\ N\\\\F=-1536\ N\\\\|F|=1536\ N

So, the magnitude of the average force exerted on the water by the blade is 1536 N.

5 0
3 years ago
A cylinder contains a gas at a temperature of 400K. Explain two ways that you can add energy to the gas and raise its temperatur
Lelechka [254]
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5 0
3 years ago
harge of uniform density (100 nC/m3) is distributed throughout a hollow cylindrical region formed by two coaxial cylindrical sur
Elden [556K]

Answer:

The magnitude of the electric field is 8.47 N/C

Explanation:

Given;

uniform charge density, λ = 100 nC/m³

inner radii of the cylinder, r =  1.0 mm and 3.0 mm

distance from the symmetry axis, R = 2.0 mm

Volume =\pi (R^2 -r^2)l\\\\Volume =\pi ((2*10^{-3})^2 -(1*10^{-3})^2)l\\\\Volume =\pi (4*10^{-6} - 1*10^{-6})l\\\\Volume = 3*10^{-6} \pi l \ m^3

Area = 2πrl

Area =2π(2 x 10⁻)l

Volume = A x d

d = Volume / Area

d = \frac{V}{A} = \frac{3*10^{-6}*\pi*l}{4\pi *10^{-3} l} = 75 *10^{-5} \ m

the magnitude of the electric field

E = \frac{\lambda *d}{\epsilon_o} = \frac{100*10^{-9} *75*10^{-5}}{8.854*10^{-12}} \\\\E = 8.47 \ N/C

Therefore, the magnitude of the electric field is 8.47 N/C

6 0
3 years ago
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