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Sladkaya [172]
3 years ago
14

Consider the chemical equation CH4 + 2 O2 → CO2 + 2 H2O. In this equation, CH4 is a

Physics
2 answers:
Reika [66]3 years ago
6 0

Answer:

\huge \boxed{\mathrm{B. \ reactant}}

\rule[225]{225}{2}

Explanation:

\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O

Balancing the Hydrogen atoms on the right side,

\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O

Balancing the Oxygen atoms on the left side,

\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O

Reactants are on the left side:

\sf \boxed{\sf CH_4 + O_2} \Rightarrow CO_2 + H_2O

\rule[225]{225}{2}

Dennis_Churaev [7]3 years ago
3 0

CH4+2O2=\ \textgreater \ CO2+2H2O
Since t<span>erms which are placed left to the arrow mark are reactants  and those placed right are products you can easily solve the task represented above. According to the information I've provided CH4 is reactant and it is </span><span>Fule. So, the correct answer is B.</span>
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What is capacitance?
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Answer:

A, the amount of charge stored per volt

Explanation:

Capacitance is defined below:

C = Q/V

Therefore capacitance is charge per volt which gets the unit farad.

7 0
2 years ago
What are the equivalent celsius and kelvin temperatures of -128 f?
Gre4nikov [31]

Answer:

128 Kelvin = 128 - 273.15 = -145.15 Celsius. Temperature conversion chart Sample temperature conversions 103.55 Kelvin to degrees Fahrenheit 39.82 degrees Fahrenheit to Kelvin

Explanation:

hope this helps have a good day

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2 years ago
A car is making a 40 mi trip. It travels the first half of the total distance 20.0 mi at 18.00 mph and the last half of the tota
sukhopar [10]

Answer: The average speed is 27,24 mph (exactly 1008/37 mph)

Explanation:

This is solved using a three rule: We know the speeds and the distances, what we can obtain from it is the time used. It is done like this:

1h--->18mi

X ---->20 mi, then X=20mi*1h/18mi= 10/9 h=1,111 h

1h--->56mi

X ---->20 mi, then X=20mi*1h/56mi= 5/14 h=0,35714 h

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5 0
3 years ago
When exercising in the heat, which of the following hydration strategies is best for temperature regulation during an event (e.g
Olegator [25]

Answer:

Your question was incomplete so here is the complete question and answer.

Q. When exercising in the heat, which of the following hydration strategies is best for temperature regulation during an event (e.g., 10K race)

a) plain water

b) 5-7 percent glucose solution

c) Glucose polymer solution of 6-8 percent

d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.

Ans. d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.

Explanation:

Temperature Regulation is an important phenomenon for the person exposed to extreme hot conditions or weather. Exercising in hot conditions increase the body temperature. Greater and intense exercise, greater the production of heat. Then the heat dissipation takes place in the form of excessive sweating which results in dehydration. That was just the brief overview of temperature regulation. Above mentioned techniques are equally good hydration techniques so there is no difference at all. You can have a plain water or glucose solutions of above mentioned percentages.

3 0
3 years ago
Relationship between frequency, amplitude, wavelength and energy in a transverse wave.
liq [111]
In a transverse wave:
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