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Yuliya22 [10]
3 years ago
9

1. Describe what happens to the gravitational when you increase mass versus when you

Physics
2 answers:
Rudik [331]3 years ago
7 0

Answer: if the mass is doubled, the force of gravity is doubled, meaning it decreases. If the distance is doubled, the force of gravity is 1/4 as strong as before

Explanation:

faust18 [17]3 years ago
6 0

Answer:If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases. If the distance is doubled, the force of gravity is one-fourth as strong as before.

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When you push a child on a swing, you are doing work on the child because _____.
max2010maxim [7]

ur answer is A or also known as

When you push a child on a swing, you are doing work on the child because  you are pushing against the force of gravity

hope this helps :)

8 0
3 years ago
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How do you double the speed in physics
Mariulka [41]

You measure the open distance between the floor and the bottom surface of the gas pedal.  Then you press the gas pedal down 1/2 of that distance.

3 0
3 years ago
If a cliff jumper leaps off the edge of a 100m cliff, how long does she fall before hitting the water? (assume zero air resistan
andrew-mc [135]
<h2>Answer:</h2>

<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

Assuming that the initial velocity of the jumper is zero, on Earth any freely falling object has an acceleration of 9.8 m/s².  

<em>✔ We have : a = v/Δt = ⇔ Δt = v/a </em>

  • Δt = (√2xgxh)/9,8
  • Δt = (14√10)/9,8
  • Δt ≈ 4,5 s

4 0
3 years ago
What is the resistance of resistor R3?
Vsevolod [243]

Answer: 2.0

Explanation: I KNOW !

5 0
3 years ago
How do you do this question? Please include free body diagrams and clear explanation, so I can understand.
vagabundo [1.1K]

Explanation:

Draw a free body diagram for each disc.

Disc A has three forces acting on it: 86.5 N up, T₁ down, and Wa down.

∑F = ma

86.5 N − T₁ − Wa = 0

Wa = 86.5 N − T₁

ma × 9.8 m/s² = 86.5 N − 55.6 N

ma = 3.2 kg

Disc B has three forces acting on it: T₁ up, T₂ down, and Wb down.

∑F = ma

T₁ − T₂ − Wb = 0

Wb = T₁ − T₂

mb × 9.8 m/s² = 55.6 N − 36.5 N

mb = 1.9 kg

Disc C has three forces acting on it: T₂ up, T₃ down, and Wc down.

∑F = ma

T₂ − T₃ − Wc = 0

Wc = T₂ − T₃

mc × 9.8 m/s² = 36.5 N − 9.6 N

mc = 2.7 kg

Disc D has two forces acting on it: T₃ up and Wd down.

∑F = ma

T₃ − Wd = 0

Wd = T₃

md × 9.8 m/s² = 9.6 N

md = 0.98 kg

3 0
3 years ago
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